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3 years ago

Describe how matter cycles through an ecosystem

1 answer:

8 0

Water is a liquid and it evaporates into the sky as a gas and than it can fall as hail or a pond can freeze over making ice which is a solid

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Determine the force the sun exerts on an object with a mass of 80.0 kg if that object is on the earth. What is the force exerted

MrRissso [65]

he has to read a tripple beam balence and mesure the pltates

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3 years ago

Read 2 more answers

Are the units of the formula ma = mv2/2 dimensionally consistent? Select the single best answer.

Vesnalui [34]

To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency

$ma = \text{Mass}\times \text{Acceleration}$

$ma = kg \cdot \frac{m}{s^2}$

At the same time we have that

$\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2$

$\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2$

$\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}$

Therefore there is not have same units and both are not consistent and the correct answer is B.

5 0

4 years ago

The Starship Enterprise is caught in a time warp and Spock is forced to use the primitive techniques of the 20th century to dete

Goryan [66]

Answer:c=0.213 J/g/K

Explanation:

Given

sample mass $(m_s)=120 gm$

initial temperature of mineral $(T_{im})=92.6$

mass of water $(m_w)=82.9$

Water initial temperature $(T_{iw})=20$

Heat capacity of calorimeter =15.3 J/k

Final Temperature is 24.8

let c be the specific heat of mineral

Heat released by mineral sample=heat absorbed by calorimeter and water

$120\times c\times (92.6-24.8)=82.9\times 4.184\times (24.8-20)+15.3\times (24.8-20)$

$c\times 67.8=14.486$

$c=0.213 J/g/K$

3 0

3 years ago

A hot-air balloon is rising straight up with a speed of 4.6 m/s. a ballast bag is released from rest relative to the balloon at

kherson [118]

The time taken by the ballast bag to reach the ground is 2.18 s

The ballast bag at rest with respect to the balloon has the upward velocity (u) of 4.6 m/s , which is the velocity of the balloon. When it is dropped from the balloon, its motion is similar to an object thrown upwards with an initial velocity u and it falls under the acceleration due to gravity g.

Taking the upward direction as positive and the downward direction as negative, the following equation of motion may be used.

$s=ut+\frac{1}{2}at^2$