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tensa zangetsu [6.8K]
4 years ago
6

What is the difference between Carbon , and NEON (periodic table). EXPLAN!

Chemistry
1 answer:
Digiron [165]4 years ago
3 0
Neon atomic number is 10


carbon atomic number is 6
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The mass percentage of hydrochloric acid within a solution is 28.00%28.00% . Given that the density of this solution is 1.1411.1
sashaice [31]

Answer:

8.76M

Explanation:

Given that

Mass from the density = 1141g

According to the given situation the computation of molarity of the solution is shown below:-

we will took HCL solution which is 1000mL

HCl = 28% by mass

So,

Mass of HCl in 1-litre solution is

= \frac{28}{100} \times 1141

Which gives the result of molar mass HCI is

= 319.48g /mol

Now,

Molarity is

= \frac{319.48}{36.45}

Which gives results of molarity is

= 8.76M

8 0
3 years ago
How do you solve pH and pOH?
ehidna [41]

Picture credit - Google images

whenever you have problem for ph and poh just make this table and go from there .

Ph = 14 - Poh

Poh = 14- Ph

8 0
4 years ago
Imagine you are digging a hole to the center of the earth. In which order would dig through them?
nadezda [96]

The order in which you would dig through the layers is

crust → upper mantle → lower mantle → outer core → inner core

See the image below.

4 0
4 years ago
Read 2 more answers
A gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from blank
lidiya [134]

Answer: -

1.34 L

Explanation: -

Initial Pressure P 1 = 39.1 bar

Initial Temperature T 1 = 643 K

Let the initial volume be V 1.

Final pressure P 2 = 87.0 bar

Final temperature T 2 = 525 K.

Final volume V 2 = 0.492 L

Using the equation

\frac{P1 V 1}{T1} = \frac{P 2 V 2}{T2}

V 1 = \frac{P2 V2 T1}{P 1 T2}

Plugging in the values

We have

V 1 = 87 bar x 0.492 L x 643 K / (39.1 bar x 525 K)

= 1.34 L

Thus, a gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from 1.34 L to 0.492L and the temperature changes from 643K to 525K

4 0
4 years ago
Read 2 more answers
A 13.00 g sample of a compound contains 4.15 g potassium (k), 3.76 g chlorine (cl), and oxygen (o). calculate the empirical form
MrRissso [65]

To solve this problem, let us all convert the mass of each element into number of moles using the formula:

moles = mass / molar mass

Where,

molar mass K = 39.10 g / mol

<span>molar mass Cl = 35.45 g / mol</span>

molar mass O = 16 g / mol

<span>and mass O = 13 g – 4.15 g – 3.76 g  = 5.09 g</span>

 

moles K = 4.15 g / (39.10 g / mol) = 0.106 mol

<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>

moles O = 5.09 g / (16 g / mol) = 0.318 mol

 

The ratio becomes:

0.106 K: 0.106 Cl: 0.318 O

We divide all numbers with the smallest number, in this case 0.106. This becomes:

K: Cl: 3O

 

Therefore the empirical formula is:

KClO_{3}

7 0
3 years ago
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