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2 years ago

What stops gravity from pulling water to the center of the earth

2 answers:

5 0

The same thing that prevents gravity from pulling to you to the center of the Earth ; electromagnetic repulsion, or more properly, electron degeneracy pressure

Alona [7]2 years ago

4 0

Magnetism, or more specifically electromagnetic repulsion

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Question 2

Alenkinab [10]

Answer:

1.53 atm

Explanation:

From the question given above, the following data were obtained:

Volume = constant

Initial pressure (P₁) = stp = 1 atm

Initial temperature (T₁) = 273 K

Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K

Final pressure (P₂) =?

Since the volume is constant, the final pressure can be obtained as follow:

P₁ / T₁ = P₂ / T₂

1 / 273 = P₂ / 417

Cross multiply

273 × P₂ = 417

Divide both side by 273

P₂ = 417 / 273

P₂ = 1.53 atm

Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.

8 0

2 years ago

PLS HELP!!

Gnesinka [82]

Answer:

from the 1st equation:

4NH3 4NO

4 *(68) 4*30

1216 X mass of NO = 536.5 g

from the 2nd Equation

2NO 2NO2

2*30 2* 46

536.5 x mass of NO2 = 822.6 grams

from the 3rd Equation

3NO2 2HNO3

3*(46) 2* (63)

822.6 X mass of nitric acid = 751.06 gram

b) % yields = ( 96.2%* 91.3% *91.4%)= 80.3%

3 0

2 years ago

A highway engineer is researching de-icing compounds for clearing ice from streets in winter. She wants a compound that has +2 i

wolverine [178]

Magnesium combined with chlorine.

How?

Look at the question .Compound has -1 charge in it .Hence it contains Halogen.
Looking at the options Option B and C contain Iodine and chlorine i.e halogens .

Now come to metals side.

Potassium has valency 1(Look the Electronic configuration below)

$\\ \sf\longmapsto 1s^22s^22p^63s^23p^64s^1$

Hence it will contain +1 charge which is omitted directly .

Now come to option C.

Magnesium has charge +2(Look at EC below

$\\ \sf\longmapsto 1s^22s^22p^63s^2$

Hence the compound formed is given by

$\\ \sf\longmapsto MgCl_2$

Hence option C is correct.

3 0

2 years ago

How many valence electrons are in beryllium?

stellarik [79]

There are 2 valence electrons

7 0

3 years ago

Use the following data to calculate the standard heat (enthalpy) of formation, Δ H°f, of manganese(IV) oxide, MnO2 ( s). 2MnO2(

lys-0071 [83]

Answer:

(A)

Explanation:

The enthalpy of formation of a substance is the enthalpy of the reaction where this substance is formed by its constituents species. So, for MnO2, the enthalpy of formation is the enthalpy of the reaction:

Mn(s) + O2(g) --> MnO2(s)

By the Hess' law, when a reaction follows steps, the enthalpy of the overall reaction is the sum of the enthalpy of the steps. In this sum, the intermediaries must be canceled, so, some changes may have to be done in the reactions. If the reaction is inverted, the signal of the enthalpy inverts too, and if it's multiplied by some constant, the enthalpy is multiplied too.

2MnO2 (s) --> 2MnO(s) + O2(g) ΔH = 264 kJ (must be inverted)

MnO2(s) + Mn(s) --> 2 MnO(s) ΔH = -240 kJ

O2(g) + 2MnO(s) --> 2MnO2(s) ΔH = -264 kJ

MnO2(s) + Mn(s) --> 2 MnO(s) ΔH = -240 kJ

---------------------------------------------------------------------

MnO is canceled, and 2MnO2 - MnO2 = MnO2 in the products because it was where have more of it:

O2(g) + Mn(s) --> MnO2(s)

ΔH = -264 + (-240) = -504 kJ

7 0

2 years ago