Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
<u>So</u><u> </u><u>another</u><u> </u><u>side's</u><u> </u><u>length</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>c</u><u>m</u>
<u>Exercise</u><u> </u><u>2</u><u>:</u>
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√<u>28</u><u>o</u><u>r</u><u> </u><u>2√7 0r 5.29 or 5.3 m</u>
Step-by-step explanation:
[Note: thanks for translating]
Answer:
51 meters
Step-by-step explanation:
Steve is turning half his backyard into a chicken fan. His backyard is a 24 m x 45 m rectangle. He wants to put a chicken wire fence that stretches diagonally from one corner to the opposite corner. How many meters of fencing will Steve need?
We are to find the meters of fencing for the diagonal.
We solve the question using Pythagoras Theorem
= c² = a² + b²
Where
c = Diagonal
a = Width
b =Length
Diagonal² = Width² + Length ²
Hence:
Diagonal ² = 45² + 24²
Diagonal = √45² + 24²
Diagonal = √(2601)
Diagonal = 51 m
Therefore, the meters of fencing for the diagonal that Steve would be needing = 51 meters
Answer:
5ft
Step-by-step explanation:
Answer:
<h3>
</h3>
Step-by-step explanation:
Use the distributive property to multiply each term of the first binomial by each term of the second binomial.
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Collect like terms
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Hope I helped!
Best regards!!
Well it is b I’m 80% sure
