Answer:
3s orbital
Explanation:
3s is the outermost orbital of magnesium and it loses electron from it, it doesnt even have 4f, 5p or 3d orbitals.
Answer:
v = 46.5 m/s
Explanation:
Given data:
Mass of car = 1210 kg
Momentum of car = 56250 kg m/s
Velocity of car = ?
Solution:
Formula:
p = mv
p = momentum
m = mass
v = velocity
Now we will put values in formula:
56250 kg m/s = 1210 kg × v
v = 56250 kg m/s / 1210 kg
v = 46.5 m/s
So a car having mass of 1210 kg with momentum 56250 kg m/s having 46.5 m/s velocity.
Answer:
the answer is 0 amu I hope it helps
Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol
Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.
W are given a chemical reaction:
To calculate the enthalpy change, we use the formula:
This is the amount of energy released when 0.1326 grams of sample was burned.
So, energy released when 1 gram of sample was burned is = 
Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:
Answer:
<em>The </em><em>correct </em><em>formula </em><em>for </em><em>Aluminium </em><em>Cyanide </em><em>is </em><em>Al(</em><em>CN)</em><em>3</em>
Explanation:
<h3>Structure of AlCN3</h3>
N
|
N----- C -----N
|
Al
<h3>
Al(CN)3 is an ion consisting of one Al3+ ion and 3 (CN)- ions held by electrostatic force of attraction!!</h3>
