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daser333 [38]
3 years ago
14

The label on a tub of margarine states that 100 g of the margarine contains 0·70 g of sodium. The sodium is present as sodium ch

loride. Calculate the mass of sodium chloride, in grams, present in a 10 g portion of the margarine. The mass of one mole of sodium chloride, NaCl, is 58·5 g.
Chemistry
1 answer:
Naddika [18.5K]3 years ago
7 0
Here you have one tenth of the original quantity of margarine.
if 100 grams of margarine has 0.70 grams of sodium, then one tenth of the margarine has one tenth of the sodium. So 10 grams of margarine has
0.070 grams of sodium chloride, keeping track of the significant figures.
If, for some reason, you need the number of moles present in 10 grams, it would be:
(#grams sodium chloride)/(#grams/mole of sodium chloride)
(0.070 grams)/(58.5 grams/mole) =  0.0012 moles of Sodium Chloride
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Question 3(1 point)
SVETLANKA909090 [29]

Answer:

<u><em>Group 8 is a group (column) of chemical elements in the periodic table. It consists of iron (Fe), ruthenium (Ru), osmium (Os) and hassium (Hs). They are all transition metals.</em></u>

Explanation:

5 0
3 years ago
Upon combustion, a 0.8009 g sample of a compound containing only carbon, hydrogen, and oxygen produces 1.6004 g CO2 and 0.6551 g
Ede4ka [16]

Answer:

C2H4O

Explanation:

We can get the answer through calculations as follows.

From the mass of carbon iv oxide produced, we can get the number of moles of carbon produced. We first divide the mass by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol

The number of moles of carbon iv oxide is 1.6004/44 = 0.0364

Since there is only one carbon atom in CO2, the number of moles of carbon is same as above

The mass of carbon in the compound is simply the number of moles multiplied by the atomic mass unit. The atomic mass unit of carbon is 12. The mass of carbon in the compound is thus 12 * 0.0364= 0.4368g

From the number of moles of water, we can get the number of moles of hydrogen. To get the number of moles of water, we need to divide the mass of water by its molar mass. Its molar mass is 18g/mol. The number of moles here is thus 0.6551/18 = 0.0364 mole

But there are 2 atoms of hydrogen in 1 mole of water and thus, the number of moles of hydrogen is 2 * 0.0364= 0.0728

The mass of hydrogen is thus 0.0728* 1 = 0.0728g

The mass of oxygen equals the mass of the compound minus that of hydrogen and that of carbon.

= 0.8009 - 0.0728 - 0.4368 = 0.2913 mole

The number of moles of oxygen is the mass of oxygen divided by its atomic mass unit.

That equals 0.2913/16 = 0.0182 mole

The empirical formula can be obtained by dividing the number of moles of each by the smallest which is that of carbon and oxygen 0.0182

H = 0.0728/0.0182 = 4

C= 0.0364/0.0182 = 2

O= 0.0182/0.0182= 1

The empirical formula is thus C2H4O

3 0
3 years ago
What is the molarity of a solution of 17.0 g of nh4br in enough h2o to make 158 ml of solution? answer in units of m?
vivado [14]
Unit of M is also mole/L, where mole is the moles of solute and L is the volume of the solution.  The latter is given: 158 mL or 0.158 L.  So we need to find out the moles of NH4Br.

Moles of NH4Br = Mass of NH4Br/molar mass of NH4Br = 17.0g/(14+1*4+79.9)g/mol = 0.1736 mole.

So, the molarity of the solution = 0.1736mole/0.158L = 1.10 mole/L = 1.10 M
6 0
3 years ago
What is the molarity of a solution which contains 0.80 mol of HCl in 250mL of<br> solution?
mariarad [96]

Answer:

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Explanation:

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moles of solute = 0.80 moles HCl

volume of solution = 250 ml = 0.250 Liter

Molarity (M) = 0.80 moles HCl / 0.250 Liters = 3.2M HCl Solution

6 0
2 years ago
What is meant by the term sensitivity in Analytical Chemistry? (a) The term refers to the limit at which the absorption instrume
ivolga24 [154]

The term sensitivity in Analytical Chemistry is "the slope of the calibration curve or a function of analyte concentration or amount".

<u>Answer:</u> Option B

<u>Explanation:</u>

In a sample, the little amounts of substances can be accurately evaluated by a method is termed as "Analytical sensitivity". This detect a target analyte like an antibody or antigen, process is considered as potential of a test to and generally demonstrated as the analyte's minimum detectable concentration.

The acceptable diagnostic sensitivity is not guaranteed by high analytical sensitivity. The percentage of individuals who have a given disarray who are identified by the method as positive for the disarray is known as "Diagnostic sensitivity".

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