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daser333 [38]
3 years ago
14

The label on a tub of margarine states that 100 g of the margarine contains 0·70 g of sodium. The sodium is present as sodium ch

loride. Calculate the mass of sodium chloride, in grams, present in a 10 g portion of the margarine. The mass of one mole of sodium chloride, NaCl, is 58·5 g.
Chemistry
1 answer:
Naddika [18.5K]3 years ago
7 0
Here you have one tenth of the original quantity of margarine.
if 100 grams of margarine has 0.70 grams of sodium, then one tenth of the margarine has one tenth of the sodium. So 10 grams of margarine has
0.070 grams of sodium chloride, keeping track of the significant figures.
If, for some reason, you need the number of moles present in 10 grams, it would be:
(#grams sodium chloride)/(#grams/mole of sodium chloride)
(0.070 grams)/(58.5 grams/mole) =  0.0012 moles of Sodium Chloride
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3 0
2 years ago
What is the molarity of a solution composed of 5.85 g of potassium iodide, KI, dissolved
Troyanec [42]

Answer:

0.282 M

General Formulas and Concepts:

<u>Chemistry - Solutions</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Molarity = moles of solute / liters of solution

Explanation:

<u>Step 1: Define</u>

5.85 g KI

0.125 L

<u>Step 2: Identify Conversions</u>

Molar Mass of K - 39.10 g/mol

Molar Mass of I - 126.90 g/mol

Molar Mass of KI - 39.10 + 126.90 = 166 g/mol

<u>Step 3: Convert</u>

<u />5.85 \ g \ KI(\frac{1 \ mol \ KI}{166 \ g \ KI} ) = 0.035241 mol KI

<u>Step 4: Find Molarity</u>

M = 0.035241 mol KI / 0.125 L

M = 0.281928

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.281928 M ≈ 0.282 M

7 0
3 years ago
Borane (BH3) adds to alkenes to form an alkylborane. In the first box draw the mechanism arrows, and in the second box draw the
OLEGan [10]

Answer:

The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.

Explanation:

The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.

6 0
3 years ago
In the iodoform test why is it necessary to add sodium hypochlorite
Kobotan [32]

Sodium hypochlorite is used in iodoform test for the oxidation of alcohol to aldehyde as shown in the image attached:

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8 0
2 years ago
A sealed container holding 0.0255 L of an ideal gas at 0.979 atm and 67 ∘ C is placed into a refrigerator and cooled to 41 ∘ C w
Aliun [14]

Answer:

0.904 atm

Explanation:

Using Gay Lusaac's law where there is no change in Volume. The pressure changes directly proportional to absolute T°

P₁/T₁ = P₂/T₂

P₁T₂/T₁

P₂ = \frac{0.979 atm * 314k }{340k}

P₂ = 0.904 atm

5 0
3 years ago
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