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daser333 [38]
3 years ago
14

The label on a tub of margarine states that 100 g of the margarine contains 0·70 g of sodium. The sodium is present as sodium ch

loride. Calculate the mass of sodium chloride, in grams, present in a 10 g portion of the margarine. The mass of one mole of sodium chloride, NaCl, is 58·5 g.
Chemistry
1 answer:
Naddika [18.5K]3 years ago
7 0
Here you have one tenth of the original quantity of margarine.
if 100 grams of margarine has 0.70 grams of sodium, then one tenth of the margarine has one tenth of the sodium. So 10 grams of margarine has
0.070 grams of sodium chloride, keeping track of the significant figures.
If, for some reason, you need the number of moles present in 10 grams, it would be:
(#grams sodium chloride)/(#grams/mole of sodium chloride)
(0.070 grams)/(58.5 grams/mole) =  0.0012 moles of Sodium Chloride
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A 0.89% (w/v) sodium chloride solution is referred to as physiological saline solution because it has the same concentration of
maks197457 [2]
1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution

=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution

2) Molarity = M = number of moles of solute / liters of solution

=> calculate the number of moles of 8.9 grams of NaCl

3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol

4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol

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Another example of chemical change is:

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3 years ago
A sample of gas with an initial volume of 12.5 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume
Kipish [7]

Answer:

Final pressure in (atm) (P1) = 6.642 atm

Explanation:

Given:

Initial volume of gas (V) = 12.5 L

Pressure (P) = 784 torr

Temperature (T) = 295 K

Final volume (V1) = 2.04 L

Final temperature (T1) = 310 K

Find:

Final pressure in (atm) (P1) = ?

Computation:

According to combine gas law method:

\frac{PV}{T} =\frac{P1V1}{T1} \\\\\frac{(784)(12.5)}{295} =\frac{(P1)(2.04)}{310}\\\\33.22 = \frac{(P1)(2.04)}{310}\\\\P1=5,048.18877

⇒ Final pressure (P1) = 5,048.18877 torr

⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760

⇒ Final pressure in (atm) (P1) = 6.642 atm

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4 years ago
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