Answer:
Step-by-step explanation:
if we have 5 numbers so to make it positive we will need more amount of +ve integers or an even amount of negative integers
so at least there must be two or four rational numbers that are negative if the total number of negative integers is not even then it will not be a positive one
Hi I got the answer I will send you soon
Answer:
the answer for number a is -14
=±22
x
=
±
2
x
2
Using the fact that 2=ln2
2
=
e
ln
2
:
=±ln22
x
=
±
e
x
ln
2
2
−ln22=±1
x
e
−
x
ln
2
2
=
±
1
−ln22−ln22=∓ln22
−
x
ln
2
2
e
−
x
ln
2
2
=
∓
ln
2
2
Here we can apply a function known as the Lambert W function. If =
x
e
x
=
a
, then =()
x
=
W
(
a
)
.
−ln22=(∓ln22)
−
x
ln
2
2
=
W
(
∓
ln
2
2
)
=−2(∓ln22)ln2
x
=
−
2
W
(
∓
ln
2
2
)
ln
2
For negative values of
x
, ()
W
(
x
)
has 2 real solutions for −−1<<0
−
e
−
1
<
x
<
0
.
−ln22
−
ln
2
2
satisfies that condition, so we have 3 real solutions overall. One real solution for the positive input, and 2 real solutions for the negative input.
I used python to calculate the values. The dps property is the level of decimal precision, because the mpmath library does arbitrary precision math. For the 3rd output line, the -1 parameter gives us the second real solution for small negative inputs. If you are interested in complex solutions, you can change that second parameter to other integer values. 0 is the default number for that parameter.
Answer:
The negative solution k = -1 is the desired solution.
Step-by-step explanation:
Let the given number = k
So, according to the question:
or, 
Now, solving this quadratic equation, we get
or, k ( k-9) + 1 (k-9) = 0
⇒( k-9)(k+1) = 0
or, ( k-9) = 0 , or (k+1) = 0
⇒ k = 9 or k = -1
Since we only want the negative solution , the k = -1 is the desired solution.
