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Bas_tet [7]
3 years ago
5

an axe used to split wood is driven into a piece of wood a distance of 3.0 cm. If mechanical advantage of the axe is 0.85. how f

ar apart is the wood split?​
Physics
1 answer:
Sidana [21]3 years ago
5 0
<h3><u>Answer;</u></h3>

3.53 cm

<h3><u>Explanation;</u></h3>

Mechanical advantage = Input distance/output distance

Input distance = 3.0 cm

Mechanical advantage = 0.85

Output distance = Input distance/Mechanical advantage

                           =  3.0/0.85

                           <u>= 3.53 cm</u>

           

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Answer:

579600J

Explanation:

Given parameters:

Height of the building  = 828m

Weight of the man  = 700N

Unknown:

Work done by the man  = ?

Solution:

The work done by the man is the same as the potential energy expended.

 Work done:

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6 0
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Microwave ovens emit microwave energy with a wavelength of 12.2 cm. What is the energy of exactly one photon of this microwave r
Iteru [2.4K]

Answer:

1.63\cdot 10^{-24} J

Explanation:

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E=\frac{hc}{\lambda}

where

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c is the speed of light

\lambda is the wavelength of the photon

In this problem, we have a microwave photon with wavelength

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The radial velocity method preferentially detects: Choose one: A. all of the above described planets equally well. B. small plan
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The radial velocity technique is able to detect planets around low-mass stars, such as M-type (red dwarf) stars.

This is due to the fact that low mass stars are more affected by the gravitational tug of planets.

When a planet orbits around a star, the star wobbles a little.

From this, we can determine the mass of the planet and its distance from the star.

hence we can say that,

option D is correct.

The radial velocity method preferentially detects large planets close to the central star

Learn more about radial velocity here:

<u>brainly.com/question/13117597</u>

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7 0
3 years ago
If a rock is thrown upward on the planet Mars with a velocity of 15 m/s, its height above the ground (in meters) after t seconds
s2008m [1.1K]

(a) The velocity (in m/s) of the rock after 1 second is 11.28 m/s.

(b) The velocity of the rock after 2 seconds is 7.56 m/s.

(c) The time for the block to hit the surface is 4.03.

(d) The velocity of the block at the maximum height is 0.

<h3>Velocity of the rock</h3>

The velocity of the rock is determined as shown below;

Height of the rock after 1 second; H(t) = 15(1) - 1.86(1)² = 13.14 m

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<h3>Velocity of the rock when t = 2 second</h3>

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<h3>Time for the rock to reach maximum height</h3>

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<h3>Velocity of the rock when it hits the surface</h3>

v = u - gt

v = 15 - 3.72(4.03)

v = 0

Learn more about velocity at maximum height here: brainly.com/question/14638187

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