On a coordinate plane, vertex A for triangle ABC is located at (6,4). Triangle ABC is dilated by a scale factor of 0.5 with the

Question

galina1969 [7]

2 years ago

12

On a coordinate plane, vertex A for triangle ABC is located at (6,4). Triangle ABC is dilated by a scale factor of 0.5 with the

center of dilation at the origin. The resulting image is triangle A'B'C'. What are the coordinates of vertex A'?

Physics

1 answer:

BigorU [14] · Answer 1 · 2022-07-23T22:26:42+03:00

<h2>Answer:</h2>

$A'(0.5\times 6,0.5 \times 4)=A'(3,2)$

<h2>Explanation:</h2>

Dilation is when you stretch something by the same amount in two perpendicular directions. In other words, dilation changes size, not overall shape. If the factor of dilation is greater than one the shape is greater than the original, else if the scale factor is less than one the shape is smaller. In this problem, we must find the coordinates of A'. Since the center of dilation is the origins, we just need to multiply the coordinates of A by 0.5. So:

$A'(0.5\times 6,0.5 \times 4)=A'(3,2)$