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rodikova [14]
4 years ago
6

Probability of breaking the branch increases when a person moves towards the end of branch of a tree​.

Physics
1 answer:
belka [17]4 years ago
5 0

Answer:

  the torque on the joint at the main stem is increased as the person moves toward the end of the branch, as is the stress within the branch.

Explanation:

In general, a branch will break when its load limits are exceeded, and/or when the stress is applied at a rate that exceeds its ability to accommodate.

Two things happen when a person moves toward the end of a tree branch:

  1. the torque on the branch joint is increased due to the increased moment arm
  2. the stress in the branch is increased because the branch gets smaller

So, if the branch doesn't break due to increased stress within the branch, the joint may fail due to its torque limit being exceeded as a person moves closer to the end.

__

From an engineering point of view, the stress limits constitute a threshold that will result in breakage with probability 1 when exceeded. When the limits are far above the applied stress, the probability of breakage is near 0. So, one could say the probability increases when the person approaches the end of the branch, since it goes from near 0 to 1.

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A rectangular loop consists of 80 turns, each carrying a current 8
liberstina [14]

Magnetic moment of loop is given by the formula

M = NiA

M = 80*8 *0.4*0.3

M = 76.8

now magnetic field is given here

B = 40 * 10^{-3} T

Now the torque on the loop is given by

T = MBsin\theta

T = 76.8* 40*10^{-3}*sin30

T = 1.536 Nm

so above is the torque on the loop.

3 0
4 years ago
In complete sentences, describe what causes the phases of the moon. (4 points)
g100num [7]
The light from the sun is reflected by the moon, we see the part of the moon that the sun shines on.The change in the phases are created from the rotation of the moon around earth.We see a full moon when the sun is opposite of the moon. The side the sun shines on the moon is what we see.
7 0
3 years ago
A 15-µF capacitor is charged to 40 V and then connected across an initially uncharged 25-µF capacitor. What is the final potenti
Kobotan [32]

Answer:

24volts

Explanation:

If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;

Q = CV where;

Q is the charge flowing across the capacitor

C is the capacitance of the capacitor. = 15-µF

V is the voltage = 40V

Q = 15×10^-6×40

Q = 0.0006coulombs

If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;

Q = CV

V = Q/C

V = 0.0006/25×10^-6

V = 24Volts

Therefore, the final potential difference across the 25-µF capacitor will be 24volts

6 0
3 years ago
Read 2 more answers
A toaster uses 1500 W of power when connected to a voltage of 120 V. What is the resistance
iVinArrow [24]

AnswerThe current through a toaster connected to a 120-V source is 8.0 A. What power is given off by the toaster? p= 8.0 A : 120V (p=960 W Page 2 7. The resistance of an electric stove eleinent at operating temperature is 11 12.

Explanation:

hope this helps =)

3 0
3 years ago
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While at a party, you pull up a sound intensity level app on your phone (everyone does stuff like that, right?), and it reads 83
allochka39001 [22]

To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as

\beta_{dB} = 10log_{10}\frac{I}{I_0}

Where,

\beta_{dB}= Sound intensity level in decibels

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB

So:

10log_{10}(\frac{32I}{I_0}) = 83

10log(\frac{I}{I_0})+10log(32) = 83

10log(\frac{I}{I_0})= 83-10log(32)

10log(\frac{I}{I_0})= 67.948dB

Therefore the sound intensity due to one person is 67.948dB

8 0
3 years ago
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