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Tomtit [17]
3 years ago
15

A toaster uses 1500 W of power when connected to a voltage of 120 V. What is the resistance

Physics
2 answers:
steposvetlana [31]3 years ago
5 0

Hello!!

For calculate the resistance of the toaster, we have to applicate formula:

\boxed{R= V^{2}/P}

\textbf{Being:}

\sqrt{} P = Potency \                           power =  1500 \ W

\sqrt{} V = Voltage = 120  \  V

\sqrt{} R = Resistance =  \               ?

\text{Then let's \textbf{replace it according} we information:}

R = (120 \ V)^{2} / 1500  \  W

R = 9.6 \ \varOmega

\textbf{Result:}\\\text{The power of the toaster is \textbf{9.6 Ohms}}

iVinArrow [24]3 years ago
3 0

AnswerThe current through a toaster connected to a 120-V source is 8.0 A. What power is given off by the toaster? p= 8.0 A : 120V (p=960 W Page 2 7. The resistance of an electric stove eleinent at operating temperature is 11 12.

Explanation:

hope this helps =)

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Answer:

It's a strength or force

Explanation:

the quantity of motion of a moving body, measured as a product of its mass and velocity

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Oil having a density of 924 kg/m 3 floats on water. A rectangular block of wood 3.79 cm high and with a density of 970 kg/m3 flo
Katena32 [7]

Answer:

x = 2.69 cm

Explanation:

We are given ;

Density of oil; ρ_oil = 924 kg/m³

Density of wood; ρ_wood = 970 kg/m³

h = 3.79cm

Density of water ( ρ_water) has a constant value of 1000 kg/m³

At equilibrium position, we have;

ρ_wood•g•h - ρ_oil•g•(h - x) - ρ_water•g•x = 0

This is because the density of oil is lower than that of water while density of wood is higher than that of oil but lower than that of water.

x is the distance below the interface between the two liquids is the bottom of the block.

Thus, let's make x the subject;

x = [(ρ_wood - ρ_oil)/(ρ_water - ρ_oil)] x h

Plugging in the relevant values to get ;

x = [(970 - 924)/(1000 - 924)] x 3.79

x = (54/76) x 3.79 = 2.69cm

5 0
4 years ago
A student, along with her backpack on the floor next to her, are in an elevator that is accelerating upward with acceleration a.
Anna007 [38]

Answer:

\mu_k = \frac{2(vt - L)}{(g + a) t^2}

Explanation:

As we know that backpack is kicked on the rough floor with speed "v"

So here as per force equation in vertical direction we know that

N - mg = ma

so normal force on the block is given as

N = mg + ma

now the magnitude of kinetic friction on the block is given as

F_f = \mu N

F_f = \mu (mg + ma)

now when bag is sliding on the floor then net deceleration of the block due to friction is given as

a = - \frac{F_f}{m}

a = -\mu_k(g + a)

now we know that bag hits the opposite wall at L distance away in time t

so we have

d = v t + \frac{1}{2}at^2

L = vt - \frac{1}{2}(\mu_k)(g + a) t^2

\mu_k = \frac{2(vt - L)}{(g + a) t^2}

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3 years ago
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Easy. All you need to do us to is to shorten the number so that it only contains 3 digits. Change 2.9979248 to 2.99. Don't forget to round the number to the last possible digit. In this case, 2.997 would round to 3.00

So the answer would be 3.00x10^8.

Why?

Well, every non-0 number to the left of the decimal point will count as a significant figure. And every number to the right of the decimal point, whether it's 0 or not, will also count as a significant figure.

The 3 to the left of the decimal point and the 2 0s to the right will add up to 3 significant figures.
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What is the force against the earth (Weight) applied by a 40kg mass?
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Here’s my work to your question.

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