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Sphinxa [80]
3 years ago
8

A rectangular loop consists of 80 turns, each carrying a current 8

Physics
1 answer:
liberstina [14]3 years ago
3 0

Magnetic moment of loop is given by the formula

M = NiA

M = 80*8 *0.4*0.3

M = 76.8

now magnetic field is given here

B = 40 * 10^{-3} T

Now the torque on the loop is given by

T = MBsin\theta

T = 76.8* 40*10^{-3}*sin30

T = 1.536 Nm

so above is the torque on the loop.

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You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.
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Given the following choices;

A) less than your true weight, mg.

B) equal to your true weight, mg.

C) more than your true weight, mg.

D) could be more or less than your true weight, mg, depending on the value of the speed.

The answer is; C

This is due to G-force. These are the perception of the weight of an object that is accelerating against gravity. We experience 1 g force on the surface of the earth because the ground exerts an upward exertion against gravity preventing as from falling to the center of the earth.  

8 0
2 years ago
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A protostar is _____.
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<u>Answer</u>

5.the stage before a star becomes a main sequence star

<u>Explanation</u>

A protostar is a small star that is still gathering its masses. When it forms enough masses it make a parent molecular cloud.

This been the case, from the choices given, the correct statement about a protostar is;

5.the stage before a star becomes a main sequence star

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Which winds are affected by specific landforms on earth's surface?
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4 0
3 years ago
What is the name of the force that opposes, or the opposite of gravity ???!!
Novosadov [1.4K]

Answer:

Tension.

<em><u>tension</u></em> is the name of force that opposes or goes opposite of gravity

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2 years ago
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A new planet is discovered beyond Pluto at a mean distance to the sun of 4004 million miles. Using Kepler's third law, determine
AVprozaik [17]

Answer:

103239.89 days

Explanation:

Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

                               a³ / T² = 7.496 × 10⁻⁶  (a.u.³/days²)

where,

a is the distance of the semi-major axis in a.u

T is the orbit time in days

Converting the mean distance of the new planet to astronomical unit (a.u.)

                       1 a.u = 9.296 × 10⁷ miles        

                                      \frac{4004 * 10^{6}}{9.296 * 10^{7}}  =  43.07\ a.u.

Substituting the values into Kepler's third law equation;

                                    \frac{(43.07)^{3}}{T^{2}}  =  7.496 * 10^{-6}  

                                    T^{2} = \frac{(43.07)^{3}}{7.496 * 10^{-6}} (days)²

                                    T^{2} = \sqrt{\frac{(43.07)^{3}}{7.496 * 10^{-6}}}

                                    T = 103239.89 days

An estimate time T for the new planet to travel around the sun in an orbit is 103239.89 days

7 0
2 years ago
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