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4 years ago

A rectangular loop consists of 80 turns, each carrying a current 8

Physics

1 answer:

liberstina [14]4 years ago

3 0

Magnetic moment of loop is given by the formula

$M = NiA$

$M = 80*8 *0.4*0.3$

$M = 76.8$

now magnetic field is given here

$B = 40 * 10^{-3} T$

Now the torque on the loop is given by

$T = MBsin\theta$

$T = 76.8* 40*10^{-3}*sin30$

$T = 1.536 Nm$

so above is the torque on the loop.

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$p_{S,1}$ , $p_{S,2}$ - Initial and final momemtums of the small object, measured in kilogram-meters per second.

$p_{B,1}$ , $p_{B,2}$ - Initial and final momentums of the big object, measured in kilogram-meters per second.

If we know that $p_{S,1} = 7\,\frac{kg\cdot m}{s}$ , $p_{B,1} = 0\,\frac{kg\cdot m}{s}$ and $p_{S, 2} = 4\,\frac{kg\cdot m}{s}$ , then the final momentum of the big object is: