Is it inhumane to keep a cat in one room?
1 answer:
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Answer:
the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Explanation:
Given that ;
the top speed of Cheetahs is almost 60 mph
In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2
The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
From the knowledge of Newton's Law;
we knew that ;
Force F = mass m × acceleration a
Also;
The net force = frictional force
so we can say that;
m×a =
where;
the coefficient of static friction is:
= 1.94
Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Answer:
S = 40.8m
Explanation:
<u>Given the following data;</u>
Initial velocity, u = 2m/s
Acceleration, a = 1.6m/s²
Time, t = 6secs
Required to find the displacement
Displacement, S = ?
The displacement of an object is given by the second equation of motion;
Where;
- S represents the displacement measured in meters.
- u represents the initial velocity measured in meters per seconds.
- t represents the time measured in seconds.
- a represents acceleration measured in meters per seconds square.
<em>Substituting into the equation, we have;</em>
S = 40.8m
<em>Therefore, the displacement of the skateboarder during this game is 40.8 meters. </em>