SQ = square root
329 = 20 * SQ (273+ t)
Do the inverse of everything on the left
Divide by 20
Square your answer (329/20)
and subtract 273 from it
((329/20)^2)-273 = t
the temperature according to my calculations was <span>-2.3975 degrees
The nearest degree, if my math is correct was -2 degrees.
I'm not sure how to graph the equation, or I can't graph it for you, rather. Try Desmos if you need to graph it.
Mark brainliest if I helped you</span>
Hello,
Please, see the attached file.
Thanks.
Answer:
hi
Step-by-step explanation:
Answer:
4x^2 +84x+440
840 in^2
Step-by-step explanation:
The length of the picture and frame is x+ 22+x= 2x+22
The width of the picture and frame is x +20+x = 2x+20
Area is length times width
A = (2x+22) *(2x+20)
We can FOIL to find the area
first 2x*2x = 4x^2
outer 2x*20 =40x
inner 2x*22 = 44x
last = 22*20 = 440
Add these together
4x^2 +40x+44x+440
4x^2 +84x+440
b. x=4
4x^2 +84x+440
4(4)^2 +84(4) +440
4*16 +336+440
64+776
840
