Answer:
We want to find:
![\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7Bn%21%7D%20%7D%7Bn%7D)
Here we can use Stirling's approximation, which says that for large values of n, we get:

Because here we are taking the limit when n tends to infinity, we can use this approximation.
Then we get.
![\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7Bn%21%7D%20%7D%7Bn%7D%20%3D%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%5Csqrt%5Bn%5D%7B%5Csqrt%7B2%2A%5Cpi%2An%7D%20%2A%28%5Cfrac%7Bn%7D%7Be%7D%20%29%5En%7D%20%7D%7Bn%7D%20%3D%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7Bn%7D%7Be%2An%7D%20%2A%5Csqrt%5B2%2An%5D%7B2%2A%5Cpi%2An%7D)
Now we can just simplify this, so we get:
![\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B1%7D%7Be%7D%20%2A%5Csqrt%5B2%2An%5D%7B2%2A%5Cpi%2An%7D%20%5C%5C)
And we can rewrite it as:

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.
Thus:

Answer:
$250
Step-by-step explanation:
The numbers in the table indicate a proportional relationship between earnings and hours worked. Among other things, that means you can find the earnings for 20 hours by using any table values that sum to 20 hours.
For example, 9 hours + 11 hours = 20 hours, so the earnings would be ...
$112.50 +137.50 = $250.00 . . . for 20 hours
You could also use 4×5 hours = 20 hours, so ...
4×$62.50 = $250 . . . for 20 hours
__
Or, you can figure ...
$37.50/(3 h) = $12.50/h
so the pay for 20 hours is ...
(20 h)×($12.50/h) = $250.00
Answer:
The final velocity v is 21.74 m/s.
Step-by-step explanation:
Given:

To find:

Solution:
As we know the third equation of motion is represented as

Substituting the values u, a and s in the above equation we get


Answer:
the exact length of the midsegment of trapezoid JKLM =
i.e 6.708 units on the graph
Step-by-step explanation:
From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.
Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:







Thus; the exact length of the midsegment of trapezoid JKLM =
i.e 6.708 units on the graph
Answer:
green by searching me on is green