1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
enot [183]
4 years ago
6

Garfield (weighing 24 lbs) took a flight from the earth to the moon (where the gravity is 1/6 the gravity here on earth) on the

space shuttle. As usual, he stuffed himself with lasagna during the entire flight and napped when he wasn't eating. Much to his delight when he got to the moon he found he weighed only 6 lbs. He immediately proclaimed a quick weight loss diet.
What is/are the REASONING to support Garfield's claim to a quick weight loss diet?

i need an answer asap please
Chemistry
1 answer:
Nana76 [90]4 years ago
3 0

Answer:

Reason: Gravitational pull of the Moon

Explanation:

Weight of Garfield is 24 lbs on the Earth. He took a flight from the Earth to the Moon where the gravity is 1/6 of the gravity on the Earth.

But when reaches the Moon he found he weighed only 6 lbs. It is due to the gravitational pull of the Moon.

Mass of an object reamins the same at every location while its weight changes due to the change in acceleration due to gravity. It is equal (on Moon) to 1/6 the of acceleration due to gravity on the earth.

You might be interested in
Which antibody does the body release when it identifies a bacterium or virus?
dlinn [17]

Explanation:

Immunoglobulin M is the first antibody produced on initial exposure to an antigen. It is also known as IgM.

It occurs as a primary response to the antigens against a particular baterium or virus. It is pentavalent in nature and has ten binding sites for antigens.

Therefore, it is concluded that when the body identifies a bacterium or a virus, it releases the antibody IgM.

6 0
3 years ago
Read 2 more answers
How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?
Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

C_{6}H_{8}O_{6}

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g

To know the percent of each element, we need to to the following:

C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0
3 years ago
In an experiment, 132 grams of potassium bromide (KNO3) was dissolved in 100 grams of water at 70 °C in 1 minute. Which of the f
pishuonlain [190]
Answer: <span>A fewer number of particles of the sample will dissolve in 1 minute.

That is because normally the solubility and rate of solubility of the salts in water increase with the temperature. This is, the higher the temperature the higher and faster the number of particles that the water can dissolve. So, at 70°C more particles will be dissolved in water in 1 minute than at 20°C.
</span>
7 0
3 years ago
Read 2 more answers
EASYYYYY!!!!!!!!
nlexa [21]

crop rotation, green manure, and bone meal

Explanation:

I just looked it up. hope it helps

6 0
3 years ago
When temperatures are below freezing, the temperature at which air becomes saturated leading to the formation of frost is the
12345 [234]

Answer:

The answer is Frost Point.

Explanation:

The temperature to which the air must be cooled, with constant pressure, to reach saturation (in relation to liquid water), is called the dew point. The dew point gives a measure of the water vapor content in the air. The higher, the greater the concentration of water vapor in the air. However, when cooling produces saturation at a temperature of 0 ° C or less, the temperature is called a frost point. The water vapor is deposited as frost on a surface whose temperature is below the dew point.

4 0
4 years ago
Other questions:
  • An object was measured by a worker as 14.6 cm long, however, the manufacturer specifications list the length of the object at 14
    9·1 answer
  • How many formula units make up 29.2 g of magnesium chloride (MgCl2)?
    10·1 answer
  • For the reaction A (g) → 3 B (g), Kp = 80100 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial pressure of A when the partia
    13·1 answer
  • What is the density of an unknown object with a mass of 225g and a volume of 500cm3
    6·1 answer
  • For the following reactions, predict the products and write the balanced formula equation, complete ionic equation, and net ioni
    7·1 answer
  • What is chemical symbol for potassium
    7·2 answers
  • 3.
    9·2 answers
  • Someone help asap its due in 10 mins
    10·1 answer
  • Silver nitrate reacts with calcium chloride as
    11·1 answer
  • A barium hydroxide solution is prepared by dissolving 2.81 g of Ba(OH)2 in water to make 25.6 mL of solution. What is the concen
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!