A.
112 kPa
Explanation:
We’ll use the combined gas law equation;
P₁V₁/T₁ = P₂V₂/T₂
Because the volume of the gas remains the same, then the V₁ and V₂ cancel out leaving us with;
P₁/T₁ = P₂/T₂
We can now replace the variables with the values given in the question. Remember to convert the temperatures to Kelvin;
25 degrees C = 298.15 K
50 degrees C = 323.15 K
103/298.15 = P₂/323.15
103/298.15 * 323.15 = P₂
111.63659 = P₂
= 112 kPa
82, Lead is Pb. The atomic number is 82, this also equals the protons. If it is stable, then the protons and electrons are going to be the same.
Answer:
Final pressure of the gas remaining in the first container is 3.5 atm
Explanation:
Since it is given that temperature is constant , we can apply -
PV=constant , where
P = Pressure of the gas
V = Volume of the container in which the gas is contained
Initially,
For container 1 -
= 4 atm
= 6 L
Finally,
For container 2 -
= 3 atm
= 1 L
For container 1 -
= ?
= 6 L
∴ = +
∴ 4×6 = (×6) +(3×1)
∴ = 3.5 atm
Answer:
Try:
1. How many atoms are in 6.5 moles of zinc?
6.5 moles 6.02 x 1023 atoms = 3.9 x 1024 atoms
1 mole
2. How many moles of argon are in a sample containing 2.4 x 1024 atoms of argon?
2.4 x 1024 atoms of argon 1 mole = 4.0 mol
6.02 x 1023 atoms
3. How many moles are in 2.5g of lithium?
2.5 grams Li 1 mole = 0.36 mol
6.9 g
4. Find the mass of 4.8moles of iron.
4.8 moles 55.8 g = 267.84 g = 270g
1 mole
Explanation:
i think i did it about right..?? :-(
Answer:
Explanation: It is already known that 1 mole of the gas( or 32g of O2) is equivalent to 22.4 Litres of the oxygen gas. So, 8g is equivalent to = (22.4/32) × 8 = 5.6 L of the gas.
