To answer the question above, let us a basis of the 1000 mL or 1 L.
volume = (0.9928 g/mL)(1000mL) = 992.8 g
Then, determine the mass of the alcohol by multiplying the total mass by the decimal equivalent of 5%.
mass of alcohol = 0.05(992.8 g) = 49.64 g
Then, determine the number of moles of ethyl alcohol by dividing the mass of alcohol by the molar mass (46 g/mol).
n = 49.64 g/ (46 g/mol) = 1.08 mol
Then, divide the number of moles by the volume (our basis is 1 L)
molarity = 1.08 mol/ 1 L = 1.08 M
<em><u>Answer</u></em><em><u> </u></em>: HBr polar
<em><u>please</u></em><em><u> </u></em><em><u>add</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>brainalist</u></em>
Answer:
Na2SO4 is equal to 0.0070401642780093 mole.
Explanation:
17) 8.4 / 20 x 100
18) 20 . 0.5150
19) 6,50% because (as you said) the law of definite proportions states that regardless of the amount, a compound is always composed of the same elements in the same proportion by mass