Answer:
0.23J/g°C
Explanation:
Given parameters:
Mass of sample = 135g
Amount of heat = 2.5kJ
Initial temperature = 19.5°c
Final temperature = 100°C
Unknown:
Specific heat capacity of the metal = ?
Solution:
The specific heat capacity of a substance is the amount of heat required to the raise the temperature of 1g of the substance by 1°C.
H = m C (T₂ - T₁ )
H is the amount of heat
m is the mass
C is the specific heat capacity
T₂ is the final temperature
T₁ is the initial temperature;
2.5 x 10³ = 135 x C x (100 - 19.5)
2500 = 10867.5C
C = 
= 0.23J/g°C
Facilitated diffusion is your answer
<span> Ethyl Mercaptan
Hope this helped!</span>
Be and B: Be is 1s2 2s2 and B is 1s2 2s2 2p1
Be has full 2 orbitals and so does B but B only has 1 electron in p so it is really unstable and easy to react. So there is a dip in ionization energies. The other questions are similar to this so if you need, feel free to ask me
Sodium is in group 1 so it has 1 valence electron (one electron in its outer shell). Sodium will be looking to lose its one valence electron in order to become more stable. Chlorine is in group 17 so it has 7 valence electrons, and therefor only needs to gain one valence electron to attain noble gas electron configuration (become stable with 8 valence electrons, just like the noble gases in group 18 have 8). Because the chlorine atom is trying to gain one electron, and the sodium atom is trying to lose one, sodium will give up its one valence electron to chlorine and the two atoms will form an ionic bond. Because chlorine is looking to gain just one electron and sodium is looking to lose the same number, the ratio of chlorine atoms to sodium atoms will be 1:1, one chlorine atom per one sodium atom.
