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3 years ago

What is the main evidence for the structure of the Earth that occur from the generation of an earthquake?

Physics

2 answers:

Alik [6]3 years ago

4 0

Answer;

-Waves

Explanation;

-The main evidence for the structure of the Earth comes from studying waves generated during an earthquake. When stress builds up and rocks at depth break, then elastic waves, just like sound waves are sent from the point of rupture. These waves speed out and move through the earth.

-When seismometers are put on the surface of the Earth, these waves can be measured. In particular, if we have enough seismic stations and the quake is big enough, then we can take all the travel time information and invert it. That means we can obtain a graph that shows the density of rock as a function of depth.

-Once we know the density we can estimate what the actual materials are. We find that the earth has a small inner core made out of iron surrounded by a larger outer liquid iron core and that is surrounded by a rocky mantle and rocky crust.

xeze [42]3 years ago

3 0

I believe that its waves

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Kiran drove from City A to City B, a distance of 228 mi. She increased her speed by 12 mi/h for the 400-mi trip from City B to C

Degger [83]

Answer:

From city A to city B her speed was 38 mi/h

Explanation:

The traveled distance can be calculated using this equation:

From city A to city B

228 mi = v · t₁

Where:

v = velocity

t₁ = time it took Kiran to travel the 228 mi from city A to city B

From city B to city C

400 mi = (v + 12 mi/h) · t₂

We also know that the entire trip took 14 h, then:

t₁ + t₂ = 14 h

So, we have a system of three equations with three unknwons:

228 mi = v · t₁

400 mi = (v + 12 mi/h) · t₂

t₁ + t₂ = 14 h

Let´s solve the third equation for t₁:

t₁ = 14 h - t₂

Now let´s replace t₁ in the first equation and solve it for t₂

228 mi = v · t₁

228 mi = v · (14 h - t₂)

228 mi/v - 14 h = - t₂

t₂ = 14 h - 228 mi/v

Now let´s replace t₂ in the second equation:

400 mi = (v + 12 mi/h) · t₂

400 mi = (v + 12 mi/h) · (14 h - 228 mi/v)

400 mi = 14 h · v - 228 mi + 168 mi - 2736 mi²/(v · h)

400 mi = 14 h · v - 60 mi - 2736 mi²/(v · h)

460 mi = 14 h · v - 2736 mi²/(v · h)

Multiplicate by v both sides of the equation:

460 mi · v = 14 h · v² - 2736 mi²/h

0 = 14 h · v² - 460 mi · v - 2737 mi²/h

Solving the quadratic equation:

v = 38 mi/h

(The other solution of the equation is negative, and therefore discarded)

From city A to city B her speed was 38 mi/h

4 0

3 years ago

Someone help please i’ll give brainliest

Fantom [35]

Directly proportional to volume, according to charles’s law

3 0

4 years ago

It is desired to construct a solenoid that will have a resistance of 4.10 Ω (at 20°C) and produce a magnetic field of 4.00 ✕ 10^

Nikolay [14]

Answer:

Part a)

$N = 754 turns$

Part b)

$L = 0.376 m$

Explanation:

Resistance of the solenoid is given as

R = 4.10 ohm

now we have

$R = \rho \frac{L}{A}$

here we know that

$\rho = 1.7 \times 10^{-8} ohm-m$

$A = \pi r^2 = \pi (\frac{0.5 \times 10^{-3}}{2})^2$

$A = 1.96 \times 10^{-7} m^2$

now from above formula

$4.10 = (1.7 \times 10^{-8})\frac{L}{1.96 \times 10^{-7}}$

$L = 47.35 m$

Part a)

now we know that it is wounded over the solenoid

so here we can say

$N(2\pi R) = L$

$N(2 \pi (0.01)) = 47.35$

$N = 754 turns$

Part b)

now length of solenoid is given as

$L = N(diameter\: of\: the\: wire)$

$L = 754(0.5 \times 10^{-3})$

$L = 0.376 m$

6 0

3 years ago

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An arctic fox has thick, dense fur in the winter and much shorter fur in the summer. How does this help the fox maintain homeost

Sonja [21]

The increased thickness of the fox's fur allows the fox to warmer in cold temperatures, while the shorter fur does the opposite.

4 0

4 years ago

Read 2 more answers

A cellphone charger has a transformer with 2000 turns in the primary coil which converts 240v a.c to 6v a.c and a rectifier that

inn [45]

Answer:

As we are converting 220V AC into a 5V DC, first we need a step-down transformer to reduce such high voltage. Here we have used 9-0-9 1A step-down transformer, which convert 220V AC to 9V AC. In transformer there are primary and secondary coils which step up or step down the voltage according to the no of turn in the coils.

Selection of proper transformer is very important. Current rating depends upon the Current requirement of Load circuit (circuit which will use the generate DC). The voltage rating should be more than the required voltage. Means if we need 5V DC, transformer should at least have a rating of 7V, because voltage regulator IC 7805 at least need 2V more i.e. 7V to provide a 5V voltage.

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2 years ago