Answer:
Initial Speed ____4m/s. Final Speed ______6m/s. Time ______5 seconds . Acceleration =________0.4m/s²
Explanation:
The acceleration is the rate of change of velocity during time t .
acceleration = Final velocity- Initial velocity/ Time
= Vf- Vi/ t
a = Δv/ Δt
= 6m/s- 4m/s/ 5s
= 2m/s/ 5s
= 0.4m/s²
It can also be defined as the difference of the initial and final velocity ( velocities measured in meters per second) during the given time t measured in seconds .The SI unit of acceleration is meter per second squared.
If the velocities are not measured in meters per second or time is not measured in seconds then the units are changed accordingly.
Answer:D
Explanation:
options A-C has the option pepsi which is an enzyme that is active in the stomach with a PH of 2.
Answer:
1. V2.
2. 299K.
3. 451K
4. 0.25 x 451 = V2 x 299
Explanation:
1. The data obtained from the question include:
Initial volume (V1) = 0.25mL
Initial temperature (T1) = 26°C
Final temperature (T2) = 178°C
Final volume (V2) =.?
2. Conversion from celsius to Kelvin temperature.
T(K) = T (°C) + 273
Initial temperature (T1) = 26°C
Initial temperature (T1) = 26°C + 273 = 299K
3. Conversion from celsius to Kelvin temperature.
T(K) = T (°C) + 273
Final temperature (T2) = 178°C
Final temperature (T1) = 178°C + 273 = 451K
4. Initial volume (V1) = 0.25mL
Initial temperature (T1) = 299K
Final temperature (T2) = 451K
Final volume (V2) =.?
V1 x T2 = V2 x T1
0.25 x 451 = V2 x 299
The answer is: D) O, F, and Kr.
Atomic radius of bromine (Br) is 114 pm.
Atomic radius of oxygen (O) is 73 pm.
Atomic radius of fluorine (F) is 72 pm.
Atomic radius of krypron (Kr) is 112 pm.
The atomic radius of a chemical element is a measure of the size of its atom.
The atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.
The atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.
A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water by <u>1</u> degrees Celsius.
<h3>What is One Calorie ?</h3>
The amount of heat energy required to raise the temperature by 1 gram of water through 1°C is known as One Calorie.
1 Calorie = 4.18 J
Thus from the above conclusion we can say that A Calorie unit used in food is equal to the amount of energy necessary to raise the temperature of 1 kilogram of water by <u>1</u> degrees Celsius.
Learn more about the One calorie here: brainly.com/question/1061571
#SPJ4
