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dedylja [7]
3 years ago
13

An unknown compound has the empirical formula CH2O and a molecular mass of 180 amu. What is the molecular formula of the compoun

d
Chemistry
1 answer:
Sav [38]3 years ago
6 0
The empirical formula gives the simplest ratio of whole numbers of components in the compound. Molecular formula gives the actual composition of elements in the compound.
empirical formula - CH₂O
Mass of one empirical unit = 12 + (1x2) + 16 = 30 a.m.u
We have to next calculate how many empirical units make up the molecular formula. For that we have to divide molecular mass by mass of one empirical unit.
Number of empirical units = 180 a.m.u / 30 = 6
There are 6 empirical units 
Therefore molecular formula = 6 x(CH₂O) = C₆H₁₂O₆
Molecular formula = C₆H₁₂O₆
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What are the cations and anions whose compounds are usually soluble?
HACTEHA [7]

Answer: -

Solubility of a substance depend on the balance of intermolecular forces between the solvent and solute, and the entropy change that accompanies this process.

Temperature and pressure also plays a role in solubility.

A solution having Group 1 cations like lithium, sodium, potassium etc are always soluble.

A solution having NH₄⁺ is soluble.

All salts with anion as nitrates, acetates, chlorates, and perchlorates are soluble in water.

8 0
3 years ago
Helpp pleasee.............​
velikii [3]

Answer:

it's answer is lithium and boron.

5 0
2 years ago
Read 2 more answers
A sample of 23.2 g of nitrogen gas is reacted with
slavikrds [6]

Answer:

1.66 moles.

Explanation:

We'll begin by calculating the number of mole in 23.2 g of nitrogen gas, N2.

This is illustrated below:

Molar mass of N2 = 2x14 = 28 g/mol

Mass of N2 = 23.2 g

Mole of N2 =.?

Mole = mass /Molar mass

Mole of N2 = 23.2/28

Mole of N2 = 0.83 mole

Next, we shall determine the number of mole in 23.2 g of Hydrogen gas, H2.

This is illustrated below:

Molar mass of H2 = 2x1 = 2 g/mol

Mass of H2 = 23.2 g

Mole of H2 =?

Mole = mass /Molar mass

Mole of H2 = 23.2/2

Mole of H2 = 11.6 moles

Next, the balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 0.83 moles will react with = (0.83 x 3) = 2.49 moles of H2.

From the calculations made above, we can see that only 2.49 moles out of 11.6 moles of H2 is required to react completely with 0.83 mole of N2.

Therefore, N2 is the limiting reactant.

Finally, we shall determine the maximum amount of NH3 produced from the reaction.

In this case, we shall use the limiting reactant because it will give the maximum yield of NH3 since all of it is consumed in the reaction.

The limiting reactant is N2 and the maximum amount of NH3 produced can be obtained as follow:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 0.83 mole of N2 will react to produce = (0.83 x 2) = 1.66 moles of NH3.

Therefore, the maximum amount of NH3 produced from the reaction is 1.66 moles.

5 0
2 years ago
Match: Substance ....... Definition Lewis acid A. Provides H+ in water Bronsted-Lowry base B. Provides OH - in water Arrhenius b
Igoryamba

Answer: F.    Electron pair acceptor

Explanation:

A Lewis acid can be properly defined as any substance such as  H+ (hygrogen ion) that can accept a pair of electron.

While a Lewis base is any substance such as (OH-) that can donate a pair of electron.

In the neutralization reaction between an acid ( H+ ) and a base (OH-). Hydrogen ion (H+ ) is the Lewis acid because it accepts an electron pair from (OH-).

Other examples of Lewis acid are;  Mg2+, K+

3 0
2 years ago
I begin the reaction with 0.45 g of beryllium. If my actual yield of beryllium chloride (mm = 79.91 g/mol) was 3.5 grams, what w
trasher [3.6K]

The percentage of yield was 777.78%

<u>Explanation:</u>

We have the equation,

Be [s]  +  2 HCl [aq]  →  BeCl 2(aq]  + H 2(g]  ↑ Be (s]  + 2 HCl [aq]  →  BeCl 2(aq]  + H 2(g] ↑

To find the percent yield we have the formula

Percentage of Yield= what you actually get/ what you should theoretically get  x 100

                                   =3.5 g/0.45 g 100

                                    = 777.78 %

The percentage of yield was 777.78%

5 0
3 years ago
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