Ask question

Ask question

All categories

3 years ago

5

If two reactions sum to an overall reaction, and the equilibrium constants for the two reactions are K1K1 and K2K2, what is the

equilibrium constant for the overall reaction?

1 answer:

inessss [21]3 years ago

7 0

Answer: The equilibrium constant for the overall reaction is $K_1\times K_2$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

a) $A\rightarrow B+C$

$K_1=\frac{[B]\times [C]}{[A]}$

b) $B+C\rightarrow D$

$K_2=\frac{[D]}{[B]\times [C]}$

For overall reaction on adding a and b we get c

c) $A\rightarrow D$

$K_3=\frac{[D]}{[A]}$

$K_3=K_1\times K_2=\frac{[B]\times [C]}{[A]}\times \frac{[D]}{[B]\times [C]}$

$K_3=K_1\times K_2=\frac{[D]}{[A]}$

The equilibrium constant for the overall reaction is $K_1\times K_2$

You might be interested in

g Tom's roommate Bob spilled crystal violet solution on his lab coat, and Tom offers to use some lye (sodium hydroxide solution)

irina [24]

Answer:

Tom is correct. The rate of reaction of Crystal violet and NaOH is first order with respect to NaOH, hence, a higher concentration of NaOH corresponds to a higher rate of reaction; a faster reaction.

This means the speed of cleaning depends on the concentration of the lye used.

Explanation:

The reaction between Crystal violet and NaOH, represented as

CV⁺ + OH⁻ → CVOH

It is a reaction that is know to turn the violet colour of the crystal violet colourless.

The rate of the reaction is also known to be second order; first order with respect to Crystal violet and first order with respect to NaOH.

This means that the rate of reaction is directly proportional to the concentration of NaOH provided all other parameters such as the rate constant and the concentration of Crystal violet are constant.

Hence, the reaction becomes faster with an increased concentration of NaOH.

So, Tom is right, concentrated lye solution would remove the stain faster.

Bob is wrong.

Hope this Helps!!!

4 0

3 years ago

Based on the concept of the global conveyor belt, what happens to ocean water as it moves from Antarctica to the equator?

Korolek [52]

Answer:

I think the answer is C

Explanation:

5 0

3 years ago

Read 2 more answers

Which of the following is accurate in describing the placement and classification of iodine?

fenix001 [56]

You can answer this question by only searching the element in the periodic table.

The atomic number of iodine, I, is 53. It is placed in the column 17 (this is the Group) and row 5 (this is the Period).

The conclusion is that the iodine is located in Period 5, Group 17, and is classified as a nonmetal.

4 0

3 years ago

In their notebook you see that it takes 9 hours for a sixth of a 0.5M solution of BC2 to react. Unfortunately, you have somewher

trasher [3.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of $BC_2$ that should used originally is $C_Z_o = 0.4492M$

Explanation:

From the question we are told that

The necessary elementary step is

$2BC_2 ----->4C + B_2$

The time taken for sixth of 0.5 M of reactant to react $t = 9 hr$

The time available is $t_a = 3.5 hr$

The desired concentration to remain $C = 0.42M$

Let Z be the reactant , Y be the first product and X the second product

Generally the elementary rate law is mathematically as

$-r_Z = kC_Z^2 = - \frac{d C_Z}{dt}$

Where k is the rate constant , $C_Z$ is the concentration of Z

From the elementary rate law we see that the reaction is second order (This because the concentration of the reactant is raised to power 2 )

For second order reaction

$\frac{1}{C_Z} - \frac{1}{C_Z_o} = kt$

Where $C_Z_o$ is the initial concentration of Z which a value of $C_Z_o = 0.5M$

From the question we are told that it take 9 hours for the concentration of the reactant to become

$C_Z = C_Z_o - \frac{1}{6} C_Z_o$

$C_Z = 0.5 - \frac{0.5}{6}$

$= 0.4167 M$

So

$\frac{1}{0.4167} - \frac{1}{0.50} = 9 k$

$0.400 = 9 k$

=> $k = 0.044\ L/ mol \cdot hr^{-1}$

For $C_Z = 0.42M$

$\frac{1}{0.42} - \frac{1}{C_Z_o} = 3.5 * 0.044$

$2.38 - 0.154 = \frac{1}{C_Z_o}$

$2.226 = \frac{1}{C_Z_o}$

$C_Z_o = \frac{1}{2.226}$

$C_Z_o = 0.4492M$

4 0

3 years ago

How much energy is required to evaporate grams of water?.

gregori [183]

Answer:

energy known as the latent heat of vaporization is required to break the hydrogen bonds. At 100 °C, 540 calories per gram of water are needed to convert one gram of liquid water to one gram of water vapour under normal pressure.

Explanation:energy known as the latent heat of vaporization is required to break the hydrogen bonds. At 100 °C, 540 calories per gram of water are needed to convert one gram of liquid water to one gram of water vapour under normal pressure.

5 0

2 years ago

Read 2 more answers