Answer:
H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)
Explanation:
We must recall that the oxides of metals are bases. These metal oxides can react with dilute acids to yield salt and water.
Bearing that in mind, we want to obtain magnesium sulfate from a metal oxide and dilute acid.
In this case we need magnesium oxide and dilute sulphuric acid. The reaction occurs as follows;
H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)
The law of conservation of energy has not been broken, provided energy is released from the fission process.
<h3>What is the law of conservation of energy?</h3>
The law states that the total energy of a process is conserved. That is, the total energy or mass of a system before and after undergoing processing remains the same. However, some of the mass/energy can be converted to another form.
When a material undergoes fission, the sum total of the mass of the particles formed should be equal to the mass of the starting materials, provided that all other things remain the same.
However, if energy is released from the fission process, it means that some of the mass of the starting materials has been converted to energy and released to the environment.
More on the law of conservation of energy can be found here: brainly.com/question/20971995
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Answer:
Iron (II) nitrate is ionic compound
Explanation:
Formula:
Fe(NO₃)₂
Iron (II) nitrate is ionic compound.
Its molecular mass is 179.85 g/mol.
NO⁻₃ is anion while Fe⁺² is cation.
Iron loses its two electron which is accepted by nitrate.
Its molecular formula can be written as FeN₂O₆.
Its color is pale green.
Its melting point is 333.65 K.
It is para magnetic compound.
it is mostly present in non hydrated form.
It is also known as ferric nitrate.
It is used to form sodium amide.
Its is also used catalyst.
<h3><u>Answer;</u></h3>
0.5 M HBr, pOH = 13.5 ; Has the lowest pH
<h3><u>Explanation;</u></h3>
From the question;
pH = -Log [OH]
or pH = 14 - pOH
Therefore;
For 0.5 M HBr
[H+] = 0.5 M
pH = - Log [0.5]
= 0.30
For; pOH = 13.5
pH = 14 - pOH
= 14 -13.5
= 0.5
For; 0.05 M HCl
pH = - log [H+]
[H+] = 0.05
pH = - Log [0.05]
= 1.30
For; pOH = 12.7
pH = 14 -pOH
= 14 -12.7
= 1.30
For; 0.005 M KOH,
pOH = - log [OH]
[OH-] = 0.005
pOH = - Log 0.005
= 2.30
pH = 14 - 2.30
= 11.7
For; pOH = 2.3
pH = 14 -pOH
= 14- 2.3
= 11.7
