Answer:
D
Explanation:
To answer this question, we will need to write the dissociation equation of aluminum trichloride.
AlCl3 ——-> Al3+ + 3Cl-
It can be seen that when aluminum chloride dissociates, it gives one mole of aluminum ion and three moles of the chloride ion.
From here we can see that the concentration of the aluminum chloride equals that of the aluminum ion while that of the chloride ion is thrice that of the aluminum chloride. This means we simply multiply 0.12M by 3 to get the molarity of the chloride ion while that of the aluminum ion remains the same
2Al₂O₃ → 4Al + 3O₂
the mole ratio is 4:3
for every 4 Al, there must be 3 O₂ in order to make 2Al₂O₃
hope this helped at all
Answer:
Data is not valid
Explanation:
When two liquids having different temperatures are mixed, regardless of the volumes, the final mix temperature will ALWAYS be between the initial temperature values.
1st Law Thermo => Law of Conservation of Energy => Energy can not be created nor destroyed, only changed in form. Mixing 22°C with 75°C will NOT result in a mix having a final temperature of 80°C.
∑ΔE = 0 => (mcΔT)₁ + (mcΔT)₂ = 0
[(20g)(1cal/g·°C)(Tₓ - 22°C)] + [(80g)(1cal/g·°C)(Tₓ - 75°C)] = 0
=> 20(Tₓ - 22) + 80(Tₓ - 75) = 0
=> 20Tₓ - 440 + 80Tₓ - 75 = 0
=> 100Tₓ = 440 + 75 = 515
=> Tₓ = (515/100)°C = 51.5°C final mix temperature
NOTE question is incorrect: The question should be:
<span>How many moles of KCLO4 can be produced with 3.45 moles of KCl. Assume all other reactants are in excess.
.......................................................................................................................
The reaction involving formation of KClO4 is
NaClO4 + KCl </span>→ KClO4 + NaCl
From above reaction, it can be seen that 1 mole of NaClO4 reacts with 1 mole of KCl to generate 1 mole of KClO4
Thus, if all other reactant are in excess, 3.45 moles of KCl will react with 3.45 moles of NaClO4 to form 3.45 moles of KClO4.
