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musickatia [10]
3 years ago
10

A lab assistant has been given data with units from an experiment to enter into the computer. Unfortunately, there are only numb

ers and no labels. Which of the
following could be a wavelength?
A. 10 m/s
B. 20 Hz
C. 30 cm
D. 40 s
Physics
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

the answer ia A

Explanation:

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Light from a laser (lambda= 406.192 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen
dsp73

Answer:

The spacing between the slits is    d = 0.00145m                

Explanation:

From the question we are told that

  The wavelength of the light is \lambda = 406.192nm = 406.192*10^{-9} m

   The distance of the slit from the screen is D = 5.937 \ m

    The number of bright fringe is n = 24

     The  length the fringes span is   L = 39.835 mm = \frac{39.835 }{1000} = 0.0398 m

The fringe width (i.e the distance of between two successive bright or dark fringe) is mathematically represented as

             \beta  = \frac{\lambda D}{d}

Where d is  the distance between the  slits

            \beta is the fringe width which can also be evaluated as

                         \beta = \frac{L}{n}

Substituting values

                        \beta = \frac{0.0398}{24}

                          \beta = 1.660 *10^{-3}

Making d the subject of formula in the above equation

                d = \frac{\lambda D}{\beta }

Substituting values

                d = \frac{406.192 *10^{-9} * 5.937 }{1.660 *10^{-3}}

                    d = 0.00145m                

           

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A 41.0 kg child swings in a swing supported by two chains, each 2.98 m long. (a) If the tension in each chain at the lowest poin
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Answer:695.5 N

Explanation:

mass of child m=41 kg

Length of chain L=2.98 m

Tension in each chain T=348 N

(a)Tension at bottom point T=348 N

At lowest Point

T+T-mg=\frac{mv^2}{L}

2T-mg=\frac{mv^2}{L}

2\times 348-41\times 9.8=\frac{41\times v^2}{2.98}

v^2=\frac{294.2\times 2.98}{41}

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(b)Force exerted by Seat will be Equal to Normal reaction

N-mg=\frac{mv^2}{L}

N=mg+\frac{mv^2}{L}

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