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3 years ago

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Two power lines run parallel for a distance of 254 m and are separated by a distance of 40.0 cm. If the current in each of the t

wo lines is 140 A and if they run in opposite directions, determine the magnitude and direction of the force each wire exerts on the other.

1 answer:

julia-pushkina [17]3 years ago

6 0

To solve this problem we will apply the concepts related to the electromagnetic force given between two cables. For this purpose we will consider the following mathematical relation,

$F = \frac{\mu_0I_1I_2L}{(2\pi d)}$

Here,

$\mu_0$ = Permeability at free space

$I_{1,2}$ = Current

L = Length

d = Distance between them

With our values we have,

$F = \frac{(4\pi*10^{-7}) (140)(140) (254)}{(2\pi (40*10^{-2}))}$

$F = 2.4892N$

Therefore the force between the wires is 2.4892 N as the current flows in oposite direction, the force is away from each other.

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The number of grams of gold you can purchase for $15 if Gold cost $8.00 per ounce is 53.26g

Dimensional analysis is a means of representing values using units.

From the question, we are told that Gold cost $8.00 per ounce, this means that:

$8.00 = 1 ounce

In order to calculate the amount in grams you can purchase for $15, we need to know the price in ounces first.

$15.00 = x

Divide both expressions

$\dfrac{8}{15} = \dfrac{1}{x}\\x = \dfrac{15}{8}\\x= 1.875 ounces$

Next is to convert the ounces to pounds.

1 pound = 16 ounces

y = 1.875 ounces

y = 1.875/16

y = 0.1171875 pounds

Conver 0.1171875 pounds to kg

Since 1kg = 2.2 pounds

z = 0.1171875 pounds

2.2z = 0.1171875

z = 0.1171875/2.2

z = 0.053267kg

Finally, convert 0.053267kg to grams using the conversion rate

1kg = 1000g

0.053267kg = y

y = 0.05326 * 1000

y = 53.26g

This shows that the amount of grams you can purchase for $15 is 53.26g

Learn more here: brainly.com/question/11819069

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3 years ago

Sherita has a mass of 50 kg and slowly climbs up a 5 m high flight of stairs how much work dose sherita do in ascending the stai

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As it travels through a crystal, a light wave is described by the function E(x,t)=Acos[(1.57×107)x−(2.93×1015)t]. In this expres

Drupady [299]

Answer:

Speed, $v=1.86\times 10^8\ m/s$

Explanation:

It is given that,

A light wave is described by the following function as :

$E(x,t)=A\ cos[(1.57\times 10^7)x-(2.93\times 10^{15})t]$ .....(1)

The general equation of wave is given by :

$E=Acos(kx-\omega t)$ ........(2)

On comparing equation (1) and (2)

$k=(1.57\times 10^7)$

$\dfrac{2\pi}{\lambda}=(1.57\times 10^7)$

$\lambda=\dfrac{2\pi}{(1.57\times 10^7)}$

Wavelength, $\lambda=4.002\times 10^{-7}\ m$

$\omega=(2.93\times 10^{15})$

$\dfrac{2\pi}{T}=(2.93\times 10^{15})$

$\dfrac{1}{T}=\dfrac{(2.93\times 10^{15})}{2\pi}$

Frequency, $f=4.66\times 10^{14}\ Hz$

Let v is the speed of the light wave. It is given by :

$v=f\times \lambda$

$v=4.66\times 10^{14}\ Hz\times 4.002\times 10^{-7}\ m$

$v=1.86\times 10^8\ m/s$

So, the speed of the light wave is $1.86\times 10^8\ m/s$ . Hence, this is the required solution.

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