the residual magnetism is coercive force or coercivity.
What is H in hysteresis?
Hysteresis is characterized as a lag of magnetic flux density (B) behind the magnetic field strength (H). All ferromagnetic materials exhibit the phenomena of hysteresis.
What is hysteresis value?
Hysteresis is defined as the deviation of the contact angle from its theoretical (and mean) value due to physical phenomena like microscopic surface defects and roughness.
What is the use of hysteresis?
In control systems, hysteresis can be used to filter signals so that the output reacts less rapidly than it otherwise would by taking recent system history into account
What is cohesive force ?
Cohesive force is the attractive force between the same type of molecules. It can also be called a collective intramolecular force. : In water, hydrogen bonds are held together by the cohesive force that creates a surface tension
Learn more Cohersive force:
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formula= W=f*d
w=work done
f=force
d=distance
w=f*d
w= 5n*0(does not budge)means does not move so distance is zero
w=5J
The work done by the children on the sumo wrestler is 5J
Explanation:
It is given that,
Length of rod, l = 14 cm = 0.14 m
Total charge, 
We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m
Electric field at the axis of rod is given by :
Where
is the linear charge density, 
So, 
E = −7849988.22 N/C
or
Negative sign shows the direction of electric field is inward in all direction. Hence, this is the required solution.
Answer:
The distance from the top of the stick would be 2l/3
Explanation:
Let the impulse 'FΔt' acts as a distance 'x' from the hinge 'H'. Assume no impulsive reaction is generated at 'H'. Let the angular velocity of the rod about 'H' just after the applied impulse be 'W'. Also consider that the center of percussion is the point on a bean attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.
Applying impulse momentum theorem for linear momentum.
FΔt = m(Wl/2), since velocity of center of mass of rod = Wl/2
Similarly applying impulse momentum theorem per angular momentum about H
FΔt * x = I * W
Where FΔt * x represents the impulsive torque and I is the moment of inertia
F Δt.x = (ml² . W)/3
Substituting FΔt
M(Wl/2) * x = (ml². W)/3
1/x = 3/2l
x = 2l/3
