All categories

4 years ago

Which of the following is the correct structural formula for ethene

Chemistry

1 answer:

lord [1]4 years ago

4 0

Ethene belongs to class of unsaturated hydrocarbons called as Alkenes. Alkene contains a double bond between two carbon atoms. And the general formula for alkene is,

CnH2n

Whereas in Ethene, n = 2, so

C₂H₄

Therefore, in ethene there are two carbon atoms doubly bonded to each other via one sigma and one pi bond. Also each carbon atom is further covalently bonded to two hydrogen atoms via sigma bond as shown below,

You might be interested in

How many significant figures are in this number? : 2.7 x 10^-3

Lady_Fox [76]

Answer:

2 significant figures i.e. 2 and 7.

Explanation:

We need to find the number of significant figures in the given number i.e. $2.7\cdot10^{-3}$ .

It has 2 significant figures i.e. 2 and 7.

It means the power of 10 doesn't count in the significant figures.

Hence, there are 2 significant figures.

6 0

3 years ago

Imagine a balloon is made from a membrane that's permeable to water but not sucrose molecules. How would the balloon be affected

Arlecino [84]

Answer:

The balloon would get larger as it gains water

Explanation:

Due to the process of osmosis, water molecules would passively move from an area of lower solute concentration, the water in the beaker, to an area of higher solute concentration, inside the balloon.

8 0

4 years ago

Given the molar absorptivity for a species X of 1600 M-1cm-1 at a wavelength of 270 nm, and 400 M-1cm-1 at a wavelength of 540 n

Andre45 [30]

Answer:

Explanation:

From the given information:

At wavelength = 270 nm

$\varepsilon x_1 = 1600 \ m^{-1} \ cm^{-1} \\ \\ \varepsilon y_1 = 200 \ m^{-1} \ cm^{-1}$

At 270 nm

Suppose x is said to be the solution for the concentration of x and y to be the solution for the concentration of y;

Then:

$\varepsilon x_1 \ l + \varepsilon y_1 \ l= 0.5 \\ \\ A = A_1 + A_2$

$1600 xl + 200 yl= 0.5$

Divide both sides by 200

$8xl + yl = \dfrac{0.5}{200}$

$8x + y = \dfrac{0.5}{200}l$

Use l = 1cm (i.e the standard length)

Then;

$8x + y = \dfrac{0.5}{200} ---- (1)$

$\varepsilon x_2 x \ l + \varepsilon y_2 y \ l= 0.5 \\ \\ 40 xl + 800 yl = 0.5$

$x + 20 y = \dfrac{0.5}{400 \ l}$

since l = 1

$x + 20 y = \dfrac{0.5}{400 \ } --- (2)$

Equating both (1) and (2) together, we have:

$8x + y - 8x - 160 y = \dfrac{0.5}{200} - \dfrac{0.5 \times 8}{400} \\ \\ \implies - 159 y = \dfrac{0.5}{200} ( 1 - \dfrac{8}{2}) \\ \\ -159 y = \dfrac{-0.5 \times 3}{200} \\ \\ 159 \ y = 0.0075 \\ \\ y = \dfrac{0.0075}{159} \\ \\ y = 0.00004716 \\ \\ y = 4.7 \times 10^{-5 } \ M$