1 mole ----------- 22.4 L ( at STP )
3.5 mols --------- ?
V = 3.5 x 22.4 / 1
V = 78.4 L
hope this helps!
Answer:
B. tension
Explanation:
a straight stretched rubber band experiences tension which is a stress that tries to pull matter apart.
Answer:
Where Blocal = local magnetic field between the two regions of the molecule
Blocal = (1-σ)B0
ΔBlocal = (1-σ1)B0 - (1-σ2)B0 = (σ2 - σ1)B0 = ΔσB0 ≈ ΔδB0 x 10∧-6
= (3.36-1.16) x 10∧-6 x B0 = 2.20 x 10∧-6B0
(a) ΔBlocal = 2.20 x 10∧-6 x 1.9T = 4.2 μT
(b) ΔBlocal = 2.20 x 10∧-6 x 16.5T = 36.3 μT
Explanation:
<span>Nitrogen gas is converted to nitrate compounds by nitrogen-fixing bacteria in soil turns nitrogen gas into root nodules. Nitrogen is the most commonly limiting nutrient in plants. Legumes use nitrogen fixing bacteria, specifically symbiotic rhizobia bacteria, within their root nodules to counter the limitation.</span>
Answer:
a) ![\Delta S](https://tex.z-dn.net/?f=%5CDelta%20S%3C0)
b) entropy of the sistem equal to a), entropy of the universe grater than a).
Explanation:
a) The change of entropy for a reversible process:
![\delta S=\frac{\delta Q}{T}](https://tex.z-dn.net/?f=%5Cdelta%20S%3D%5Cfrac%7B%5Cdelta%20Q%7D%7BT%7D)
![\Delta S=\frac{Q}{T}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cfrac%7BQ%7D%7BT%7D)
The energy balance:
![\delta U=[tex]\delta Q- \delta W](https://tex.z-dn.net/?f=%5Cdelta%20U%3D%5Btex%5D%5Cdelta%20Q-%20%5Cdelta%20W)
If the process is isothermical the U doesn't change:
![0=[tex]\delta Q- \delta W](https://tex.z-dn.net/?f=0%3D%5Btex%5D%5Cdelta%20Q-%20%5Cdelta%20W)
![\delta Q= \delta W](https://tex.z-dn.net/?f=%5Cdelta%20Q%3D%20%5Cdelta%20W)
![Q= W](https://tex.z-dn.net/?f=Q%3D%20W)
The work:
![W=\int_{V1}^{V2}P*dV](https://tex.z-dn.net/?f=W%3D%5Cint_%7BV1%7D%5E%7BV2%7DP%2AdV)
If it is an ideal gas:
![P=\frac{n*R*T}{V}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7Bn%2AR%2AT%7D%7BV%7D)
![W=\int_{V1}^{V2}\frac{n*R*T}{V}*dV](https://tex.z-dn.net/?f=W%3D%5Cint_%7BV1%7D%5E%7BV2%7D%5Cfrac%7Bn%2AR%2AT%7D%7BV%7D%2AdV)
Solving:
![W=n*R*T*ln(V2/V1)](https://tex.z-dn.net/?f=W%3Dn%2AR%2AT%2Aln%28V2%2FV1%29)
Replacing:
![\Delta S=\frac{n*R*T*ln(V2/V1)}{T}](https://tex.z-dn.net/?f=%5CDelta%20S%3D%5Cfrac%7Bn%2AR%2AT%2Aln%28V2%2FV1%29%7D%7BT%7D)
![\Delta S=n*R*ln(V2/V1)}](https://tex.z-dn.net/?f=%5CDelta%20S%3Dn%2AR%2Aln%28V2%2FV1%29%7D)
Given that it's a compression: V2<V1 and ln(V2/V1)<0. So:
![\Delta S](https://tex.z-dn.net/?f=%5CDelta%20S%3C0)
b) The entropy change of the sistem will be equal to the calculated in a), but the change of entropy of the universe will be 0 in a) (reversible process) and in b) has to be positive given that it is an irreversible process.