Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г. магния потребуется 11,2 л. хлора.
Answer:
a state of matter created when particles, called bosons, are cooled to near absolute zero (-273.15 degrees Celsius, or -460 degrees Fahrenheit).
Explanation:
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Answer:
The solubility of AgCl in water decreases.
Explanation:
When we add AgNO₃ we are adding silver ions. Therefore, in addition to the dissociation of AgCl, the following process also contributes to the total concentration of the common silver ions in solution:
AgNO₃ (s) → Ag⁺ (aq) + NO₃⁻ (aq)
The solubility equilibrium of AgCl is:
AgCl(s) ⇄ Ag⁺ (aq) + Cl⁻ (aq)
If AgNO₃ is added to a saturated AgCl solution, the increase in [Ag⁺] will make the ion product greater than the solubility product:
Q = [Ag⁺]₀[ Cl⁻]₀ > Ksp
<u>To reestablish equilibrium, some AgCl will precipitate out of the solution</u>, as Le Châtelier’s principle would predict, until the ion product is once again equal to Ksp.
The effect of adding a common ion, then, is a decrease in the solubility of the salt (AgCl) in solution. Note that in this case [Ag⁺] is no longer equal to [Cl⁻] at equilibrium.
When we make food, our chemicals in our bodies, cleaning products etc