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dolphi86 [110]
3 years ago
11

What provides clues about how igneous rocks were formed? A color B Texture C Luster D Streaks

Chemistry
2 answers:
Troyanec [42]3 years ago
8 0
Did you ever find the answerr? if you did can I pls know ,Ty.
Pani-rosa [81]3 years ago
7 0

the correct answer is C. Texture  

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D you welcome lovey.
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3 years ago
What is the gram formula mass of Na2CO3 multiplied by 10H2O
Lerok [7]
Enter a chemical formula to calculate its molar mass and elemental composition: Notice: your ... as a zero '0' Molar mass of Na2Co3*10H2O<span> is 402.9319 g/mol ...</span>
6 0
3 years ago
One way to determine the pH of a solution is to measure the concentration of the acid and base forms of the indicator colorimetr
ki77a [65]

Answer:

pH = 4.26

Explanation:

Bromocresol green is a commonly used pH indicator. The concentration ratio of the acid form to base form explains its color, which reflects the pH of the medium.

C₂₁H₁₄Br₄O₅S + H₂O ⇄ C₂₁H₁₃Br₄O₅S⁻ + H₃O⁺

      acid                       conjugate base

We can calculate the pH through Henderson-Hasselbalch's equation:

pH=pKa+log(\frac{[base]}{[acid]} )=4.66+log(\frac{1}{2.49} )=4.26

7 0
3 years ago
What is the pH of solution if the concentration of [H3O+] = 0.000558?
lina2011 [118]

Answer:

3.25

Explanation:

pH = -log[H3O+]

-log(0.000558)=3.25

7 0
4 years ago
How many atoms are present in 98.1 grams of Ar? You may report your numerical answer in scientific notation use e-notation.
Andrei [34K]

Answer:

1.48 × 10²⁴ atoms

Explanation:

Step 1: Calculate the moles of argon

Argon is a noble gas, whose molar mass is 39.95 g/mol. We will use this data to find the moles corresponding to 98.1 grams of argon.

98.1g \times \frac{1mol}{39.95g} =2.46 mol

Step 2: Calculate the atoms of argon

In order to calculate the number of atoms of argon in 2.46 moles of argon, we have to consider the Avogadro's number: there are 6.02 × 10²³ atoms of Ar in 1 mole of Ar.

2.46mol \times \frac{6.02 \times 10^{23}atoms  }{1mol} = 1.48 \times 10^{24}atoms

6 0
3 years ago
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