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3 years ago

What is the abbreviated electron configuration of iodine (I)?

Chemistry

1 answer:

castortr0y [4]3 years ago

5 0

Answer:

b) [Kr] 5s² 4d¹⁰ 5p⁵

Explanation:

Properties of iodine:

Iodine is present in group seventeen.

It is halogen element.

Its atomic mass is 127 amu.

Its atomic number is 53.

It is present in solid form.

It is crystalline in nature.

It is very corrosive and has pungent odor.

It can not react with oxygen and nitrogen.

Electronic configuration:

I₅₅ = 1s² 2s² 2p⁶ 3s³ 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵

Abbreviated electronic configuration:

I₅₅ = [Kr] 5s² 4d¹⁰ 5p⁵

Abbreviated electronic configuration is shortest electronic configuration by using the noble gases.

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2 years ago

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Answer:

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3 years ago

How many moles of oxygen atoms are in 7.9E-1 moles of CO_2

Ilya [14]

Answer:

The number of moles of O atom in $(7.9\times10^{-1})$ mol of $CO_{2}$ = 1.6

Explanation:

1 molecule of $CO_{2}$ contains 2 atoms of O

So, $(6.023\times 10^{23})$ molecules of $CO_{2}$ contains $(2\times6.023\times10^{23})$ atoms of O.

We know that 1 mol of an atom/molecule/ion represents $6.023\times10^{23}$ numbers of atoms/molecules/ions respectively.

So, $(6.023\times 10^{23})$ molecules of $CO_{2}$ is equal to 1 mol of $CO_{2}$ .

$(2\times6.023\times10^{23})$ atoms of O is equal to 2 moles of O atom.

Hence, 1 mol of $CO_{2}$ contains 2 moles of O atom.

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2 years ago