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JulsSmile [24]
3 years ago
12

What is the abbreviated electron configuration of iodine (I)?

Chemistry
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

b) [Kr] 5s² 4d¹⁰ 5p⁵

Explanation:

Properties of iodine:

Iodine is present in group seventeen.

It is halogen element.

Its atomic mass is 127 amu.

Its atomic number is  53.

It is present in solid form.  

It is crystalline in nature.  

It is very corrosive and has pungent odor.  

It can not react with oxygen and nitrogen.  

Electronic configuration:

I₅₅ = 1s² 2s² 2p⁶  3s³ 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵

Abbreviated electronic configuration:

I₅₅ = [Kr] 5s² 4d¹⁰ 5p⁵

Abbreviated electronic configuration is shortest electronic configuration by using the noble gases.

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Which element experiences greater London dispersion forces
natali 33 [55]
Its d its the only one that makes sense


8 0
3 years ago
If 0.8675 g of KHP requires 24.56 mL of an NaOH solution to reach the equivalence
ValentinkaMS [17]

Answer:

M_{base}=0.173M

Explanation:

Hello there!

In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:

n_{acid}=M_{base}V_{base}

Thus, by solving for the volume of the base as NaOH, we obtain:

M_{base}=\frac{n_{acid}}{V_{base}} \\\\M_{base}=\frac{0.8675g*\frac{1mol}{204.22g} }{0.02456L} \\\\M_{base}=0.173M

Best regards!

6 0
3 years ago
Calculate the molarity of a solution of potassium hydroxide if 19.55 mL of KOH is required for the titration of a 20.20 mL sampl
VMariaS [17]

Answer:

The correct answer is 0.3582 M.

Explanation:

Based on the given information, the volume of KOH given is 19.55 ml, the volume of sulfuric acid given is 20.20 ml, and the molarity of sulfuric acid is 0.3467 M. There is a need to find the molarity of KOH.

The formula to use in the given case is,

M1V1 = M2V2

Here M1 is the molarity of KOH, V1 is the volume of KOH, M2 is the molarity of sulfuric acid, and V2 is the volume of H2SO4.

Here V1 is 19.55 ml, M2 is 0.3467 M, and V2 is 2020 ml.

Now putting the values in the equation we get,

M1 * 19.55 = 0.3467 * 20.20

M1 * 19.55 = 7.00334

M1 = 7.00334/19.55

M1 = 0.3582 M

Hence, the molarity of the given KOH is 0.3582.

5 0
2 years ago
A pressure of 125,400 Pa is equal to<br> kPa.
dalvyx [7]

Answer:

it is equal to 125 kPa

Explanation:

move the decimal 3 to the left

3 0
3 years ago
The radius of a potassium atom is 231 pm. How many potassium atoms would have to be laid side by side to span a distance of 4.77
Softa [21]
To determine the number of potassium laid side by side by a given distance, we simply divide the total distance to the diameter of each atom. The diameter is twice the radius of the atom. We calculate as follows:

number of atoms = 4770 / 231x10^-12 = 2.06x10^13 atoms
3 0
3 years ago
Read 2 more answers
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