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3 years ago

What is the abbreviated electron configuration of iodine (I)?

Chemistry

1 answer:

castortr0y [4]3 years ago

5 0

Answer:

b) [Kr] 5s² 4d¹⁰ 5p⁵

Explanation:

Properties of iodine:

Iodine is present in group seventeen.

It is halogen element.

Its atomic mass is 127 amu.

Its atomic number is 53.

It is present in solid form.

It is crystalline in nature.

It is very corrosive and has pungent odor.

It can not react with oxygen and nitrogen.

Electronic configuration:

I₅₅ = 1s² 2s² 2p⁶ 3s³ 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵

Abbreviated electronic configuration:

I₅₅ = [Kr] 5s² 4d¹⁰ 5p⁵

Abbreviated electronic configuration is shortest electronic configuration by using the noble gases.

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How many acetate ions are formed when three formula units of zinc acetate dissociate?

jeyben [28]

A formula unit is the same as the empirical formula of a compound or an ionic molecule. It is the lowest ratio of the atoms in the compound or ion. Zinc acetate ions dissociates into zinc ions and acetate ions. The dissociation reaction is expressed as follows:
Zn(O2CCH3)2 = Zn2+ + 2(O2CCH3)1-

We determine the amount of acetate ions produced as follows:

Moles Zn(O2CCH3)2 = (3 formula units Zn(O2CCH3)2) ( 1 mol / 6.022x10^23 formula units) = 4.98x10^-24 mol Zn(O2CCH3)2
moles (O2CCH3)1- = 4.98x10^-24 mol Zn(O2CCH3)2 ( 2 mol (O2CCH3)1- / 1 mol Zn(O2CCH3)2 ) = 9.96x10^-24 mol (O2CCH3)1-
# of acetate ions = 9.96x10^-24 mol (O2CCH3)1- ( 6.022x10^23 ions / 1 mol (O2CCH3)1-) = 6 acetate ions

3 0

3 years ago

A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M Na

s344n2d4d5 [400]

Answer:

a: before equivalence point

b: equivalence point

c: before equivalence point

d: after the eqivalence point

e: before equivalence point

f: after the eqivalence point

Explanation:

Balanced equation of reaction:

NaOH +HCl =NaCl +H2O;

Volume of HCl is fixed and it 100ml and concentration is 1.0M

N1 and N2 normality of HCl and NaOH respectively;

V1 and V2 volume of HCl and NaOH respectively;

we have given molarity but we need normality;

$Normality=molarity \times n-factor$

<em>but in case of NaOH and HCl n-factor is 1 for each.</em>

hence

normality=molarity;

At equivalence point: $N_1V_1=N_2V_2$

Before equivalence point : $N_1V_1>N_2V_2$

After the equivalence point: $N_1V_1$

$N_1V_1=100\times1=100$

case a: 5.00 mL of 1.00 M NaOH

$N_2V_2=5\times1=5$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case b: 100mL of 1.00 M NaOH

$N_2V_2=100\times1=100$

$N_1V_1=N_2V_2$ hence it is equivalence point

case c: 10.0 mL of 1.00 M NaOH

$N_2V_2=10\times1=10$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case d: 150 mL of 1.00 M NaOH

$N_2V_2=150\times1=150$

$N_1V_1$ hence it is after the eqivalence point

case e: 50.0 mL of 1.00 M NaOH

$N_2V_2=50\times1=50$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case f: 200 mL of 1.00 M NaOH

$N_2V_2=200\times1=200$

$N_1V_1$ hence it is after the eqivalence point

7 0

3 years ago

Which of the following is the best example of potential energy?

strojnjashka [21]

Answer :

A car stopped at the top of a hill

Explanation :

Definition of potential energy : energy stored that depends upon the relative position of various parts of a system

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2 years ago

What are some interesting facts about earths inner core?

liraira [26]

1. It is made out of Iron. 2. It's the hottest layer of the Earth, like super super hot.

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2 years ago

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Sulfur dioxide is a main component of: photochemical smog, thermal inversion, industrial smog.

DedPeter [7]

The correct answer is industrial smog. This type of smog exists in coal power plants which creates smoke and sulfur dioxide which may mix with fog creating a thick blanket of haze. Sulfur dioxide is one primary component of an industrial smog.

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2 years ago

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