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2 years ago

Explain what happens when water reacts with sodium metal. Support your answer with the relevant

1 answer:

4 0

Sodium metal reacts rapidly with water to form a solution of sodium hydroxide (NaOH) and hydrogen gas (H2). This reaction is exothermic.

Equation:

2Na + 2H²0 --------}- 2NaOH + H²

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Aluminum oxide is formed when aluminum combines with oxygen in the air. How many grams of Al2O3 are formed when 13.6 mol of Al r

LenKa [72]

Answer:

4Al + 3O2 → 2Al2O3 a. If you use 2.3 moles of Al, how many moles of Al2O3 can ... How many grams of Al2O3 are produced from the reaction of 5 moles of Al?

Explanation:

3 0

2 years ago

Which of the following is generally FALSE? Group of answer choices Elements in the same group have the same valence electron con

Whitepunk [10]

Answer: Option (c) is the correct answer.

Explanation:

Generally, when we move from top to bottom in a group then there occur increase in the number of electrons due to which there will also occur increase in the number of shells.

As atomic size is the distance between the nucleus and valence shell of an atom. Hence, more is the number of shells present in an atom more will be its atomic radius.

Thus, we can conclude that the statement atomic radius of elements in a group decreases as you go from top to bottom, is generally FALSE.

3 0

2 years ago

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressur

fenix001 [56]

At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.

<h3>What is Henry's Law ?</h3>

Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.

<h3>What is relationship between Henry's Law constant and Solubility ?</h3>

The solubility of gas is directly proportional to partial pressure.

It is expressed as:

$S_{\text{gas}} = K_{H} P_{\text{gas}}$

where,

$S_{\text{gas}}$ = Solubility of gas

$K_{H}$ = Henry's Law constant

$P_{\text{gas}}$ = Partial pressure of gas

Now put the values in above expression we get

$S_{\text{gas}} = K_{H} P_{\text{gas}}$

0.080M = $K_{H}$ × 1.7 atm

$K_{H} = \frac{0.080\ M}{1.7\ \text{atm}}$

= 0.047 M/atm

Now we have to find the partial pressure of He

$S_{\text{gas}} = K_{H} P_{\text{gas}}$

0.200 M = 0.047 M/atm × $P_{\text{gas}}$

$P_{\text{gas}} = \frac{0.200 M}{0.047\ \text{M/atm}}$

= 4.25 atm

Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.

Learn more about the Henry's Law here: brainly.com/question/23204201

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3 0

1 year ago

One hundred million copper atoms are arranged in a line. Which is a reasonable estimate for the length of this line?

Anettt [7]

The size of an atom is roughly 10^-10 metres

10^-10 • 100,000,000 = 0.01 metres

Since 1 metre = 100 centimetre

0.01 x 100 = 1 centimetre

There’s your answer

8 0

2 years ago

The balanced equation for combustion in an acetylene torch is shown below: 2C2H2 + 5O2 → 4CO2 + 2H2O The acetylene tank contains

andriy [413]

Answer: 67.2 moles

Explanation: $2C_2H5+5O_2\rightarrow 4CO_2+2H_2O$

According to the given balanced equation, 2 moles of acetylene $C_2H_2$ combine with 5 moles of oxygen $O_2$ to produce 4 moles of carbon dioxide $CO_2$ .

Thus if 2 moles of acetylene $C_2H_2$ combine with = 5 moles of oxygen $O_2$

35 moles of acetylene $C_2H_2$ combine with= $\frac{5}{2}\times {35}=87.5$ moles of oxygen $O_2$

But as only 84 moles of oxygen are available, acetylene is not a limiting reagent.

5 moles of oxygen $O_2$ reacts with = 2 moles of acetylene $C_2H_2$

84 moles of oxygen $O_2$ reacts with= $\frac{2}{5}\times {84}=33.6$ moles of acetylene $C_2H_2$

Thus Oxygen is the limiting reagent as it limits the formation of products. Acetylene is excess reagent as it is present in excess.

2 moles of acetylene $C_2H_2$ produce= 4 moles of carbon dioxide $CO_2$ .

33.6 moles of acetylene $C_2H_2$ produce= $\frac{4}{2}\times {33.6}=67.2$ moles of of carbon dioxide $CO_2$ .

8 0

3 years ago

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