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Taya2010 [7]
3 years ago
9

Which of the following correctly organizes Mendel’s laws of hereditary from the third to the first?

Chemistry
1 answer:
dem82 [27]3 years ago
5 0

Mendel's laws of hereditary  are

1) Segregation

2) Independence

3) Dominance

Since you putting them from third to first, your

answer would be A. Dominance, Independence, Segregation.

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PLEASE HURRY AND SHOW WORK
IgorC [24]

Answer:

The answer to your question is   P = 1.64 atm

Explanation:

Data

Volume = 2.5 x 10⁷ L

Temperature = 22°C

Pressure = ?

Moles = 1.7 x 10⁶

R = 0.082 atm L/ mol°K

Process

1.- Convert temperature to °K

Temperature = 22 + 273

                      = 295°K

2.- Use the Ideal gas law to solve this problem

                PV = nRT

- Solve for P

                P = nRT / V

- Substitution

                P = (1.7 x 10⁶)(0.082)(295) / 2.5 x 10⁷

- Simplification

                P = 41123000 / 2.5 x 10⁷

- Result

                P = 1.64 atm

3 0
3 years ago
Which property determines whether an acid is weak or strong?
julsineya [31]

Answer:

The property that determines whether an acid is weak or strong is its ability to dissociate and form ions.

Explanation:

8 0
3 years ago
Read 2 more answers
Para que sirven los modelos atómicos
kolezko [41]

Answer:

mi no speak espanol

Explanation:

6 0
3 years ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
3 years ago
In the liquid and solid states, molecules are held together by attractions called intermolecular forces. there are several types
BaLLatris [955]
<span>Since these molecules are all non-polar, the only intermolecular force of attraction will be London dispersion forces. Since these increase by the size of the molecule, the boiling points will decrease in the same order: Parafin > Heptadecane > hexane > 2,2-dimethylbutane > propane For these two, hexane > 2,2-dimethylbutane, dispersion forces are greater in a molecule which is longer and unbranched compared to one which is branched and more compact.</span>
3 0
3 years ago
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