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telo118 [61]
3 years ago
5

Ionic equation for Anode positive electrode

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

A half-equation shows you what happens at one of the electrodes during electrolysis. Electrons are shown as e-. A half-equation is balanced by adding, or taking away, a number of electrons equal to the total number of charges on the ions in the equation.

Explanation:

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Copper crystallizes in a face-centered cubic unit cell. the density of copper is 8.94 g/cm3. calculate the length of the edge of
Ilia_Sergeevich [38]
<span>361.4 pm is the length of the edge of the unit cell. First, let's calculate the average volume each atom is taking. Start with calculating how many moles of copper we have in a cubic centimeter by looking up the atomic weight. Atomic weight copper = 63.546 Now divide the mass by the atomic weight, getting 8.94 g / 63.546 g/mol = 0.140685488 mol And multiply by Avogadro's number to get the number of atoms: 0.140685488 * 6.022140857x10^23 = 8.472278233x10^22 Now examine the face-centered cubic unit cell to see how many atoms worth of space it consumes. There is 1 atom at each of the 8 corners and each of those atoms is shared between 8 unit cells for for a space consumption of 8/8 = 1 atom. And there are 6 faces, each with an atom in the center, each of which is shared between 2 unit cells for a space consumption of 6/2 = 3 atoms. So each unit cell consumes as much space as 4 atoms. Let's divide the number of atoms in that cubic centimeter by 4 to determine the number of unit cells in that volume. 8.472278233x10^22 / 4 = 2.118069558x10^22 Now calculate the volume each unit cell occupies. 1 cm^3 / 2.118069558x10^22 = 4.721280262x10^-23 cm^3 Let's get the cube root to get the length of an edge. (4.721280262x10^-23 cm^3)^(1/3) = 3.61426x10^-08 cm Now let's convert from cm to pm. 3.61426x10^-08 cm / 100 cm/m * 1x10^12 pm/m = 361.4 pm Doing an independent search for the Crystallographic Features of Copper, I see that the Lattice Parameter for copper at at 293 K is 3.6147 x 10^-10 m which is in very close agreement with the calculated amount above. And since metals expand and contract with heat and cold, I assume the slight difference in values is due to the density figure given being determined at a temperature lower than 293 K.</span>
4 0
3 years ago
For which nuclear power problem do we not yet have a workable solution?
SCORPION-xisa [38]

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If nuclear waste is wasted in atmosphere or into oceans and lagre lakes, eventually it will come in contact with living organisms.

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8 0
4 years ago
H-Chromen is
Keith_Richards [23]

Answer:

a

<h2> benzo(b)pyram hope helpful </h2>
3 0
3 years ago
What would happen if the digestive system was not working?
kogti [31]

Answer:

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3 0
3 years ago
Sulfur powder (S) and oxygen gas (O2) undergo a
Zigmanuir [339]

S (s) + O₂ (g) → SO₂ (aq) represents this chemical reaction

<h3>Further explanation</h3>

In stating a chemical equation it can be done in the form of a word or a chemical formula

A word equation will include the words of the reactants, products, form of the compound (liquid, gas, solid), the total concentration/quantity of the reactants and products which can be expressed in mass, moles, or volume

The questions statement above shows that sulfur powder (S) and oxygen gas (O₂) are reactants (located on the left of the reaction equation), and sulfur dioxide (SO₂) is the product of the reaction (stated in the problem there is the word "to form") which is located on the right

So the complete reaction

S (s) + O₂ (g) → SO₂ (aq)

5 0
3 years ago
Read 2 more answers
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