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telo118 [61]
3 years ago
5

Ionic equation for Anode positive electrode

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

A half-equation shows you what happens at one of the electrodes during electrolysis. Electrons are shown as e-. A half-equation is balanced by adding, or taking away, a number of electrons equal to the total number of charges on the ions in the equation.

Explanation:

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olasank [31]
Use Arrhenius equation: 
k = A*exp(-Ea/RT) 
We have: 
1.35x10^2/s = A*exp(-85600/(8.314*298.15)) 
or: A = 1.342x10^17/s 
It is a piece of cake to calculate: 
k = 1.342x10^17*exp(-85600/(8.314*348.15)) 
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2 years ago
Which one of the following processes produces a decrease in the entropy of the system?a, precipitation of AgCl(s) from Ag+(aq) a
Usimov [2.4K]

Answer:  precipitation of AgCl(s) from Ag^+(aq) and Cl^-(aq) ions in solution

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

\Delta S is positive when randomness increases and \Delta S is negative when randomness decreases.

a) precipitation of AgCl(s) from Ag^+(aq) and Cl^-(aq) ions in solution : As ions are getting solidified, entropy decreases.

b) dissolution of LiOH(s) in water: The compounds dissociates into ions, entropy increases.

c) melting solid gold into liquid gold: The randomness increases, entropy increases.

d) evaporation of Hg(l) to form Hg(g) : The randomness increases, entropy increases.

e)  mixing of two gases into one container : The randomness increases, entropy increases.

4 0
3 years ago
Help! 7th grade science!
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2 years ago
You take three compounds consisting of two elements and decompose them. To determine the relative masses of X, Y, and Z, you col
miss Akunina [59]

Answer:

a) LAW OF MULTIPLE PROPORTIONS

b) 0.095g, 0.71g, 0.285g respectively

c) X2Y, YZ15, X6Y

d) hence mass of compound X = 21 x 0.045 = 0.95g

mass of compound Y = 21 x 0.955 = 20.05g

Explanation:

a) The assumptions made in solving this questions is the application of the LAW OF MULTIPLE PROPORTIONS. The Law of multiple proportions states that if two elements A and B combine together to form more than one compound, then the several masses of A which chemically combine with a fixed mass of B is in a simple ratio.

for example, copper forms two oxides ; copper(I) oxide (CuO) and copper(ii) oxide(Cu2O), it is possible for the two samples of the oxides to be reduced to Cu by reacting with Hydrogen gas. as such, certain masses of oxygen combine separately with a fixed mass of Cu. then the ratios of Cu are then determined.

b) To calculate the relative masses, we take note of the three compounds given, they all have some amount of Y in them, hence we can use Y  as our relative mass, this implies that the relative mass of Y = 1g

mass of X = 0.4g

mass of Y = 4.2g

amount of X in 1g of Y = 0.4 x 1 /4.2

= 0.095g

for compound 2;

mass of Y = 1.4g

mass of Z = 1.0g

amount of Z in 1g of Y =1.0 x 1 /1.4

= 0.71g

for compound 3;

mass of X = 2.0g

mass of Y = 7.0g

amount of X in 1g of Y = 1 x 2/7

= 0.285g

c) Applying the law of multiple proportions; since elements X and Z combine with a fixed mass of Y, they must bear a simple ratio;

compound 1/compound 3 = 0.095/0.285

= 1/3

compound 1/compound 2 = 0.095/0.71

= 2/15

compound 2/ compound 3 = 0.71/0.285

= 5/2

formular for compound 1 = X2Y

formula for compound 2 = YZ15

formular for compound 3 = X6Y

d) from the formular X2Y, we can get the amount of each product in XY using the ratios

%of compound XY in X = mass of compound X / total Mass

= 0.2/4.4 = 4.5%

as such in a 21g of compound XY, %of compound Y = 1 - %of compound X = 95.5%

hence mass of compound X = 21 x 0.045 = 0.95g

mass of compound Y = 21 x 0.955 = 20.05g

5 0
3 years ago
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