Question

from right circular cylinder with height 10 cm and radius of base 6 CM a right circular cone of the same height and base is remote find the volume of the remaining solid

Answer 1

Answer:

753.98 cubic cm.

Step-by-step explanation:

We have been given that from right circular cylinder with height 10 cm and radius of base 6 cm, a right circular cone of the same height and base is removed.

To find the area of remaining solid we will subtract volume of cone from volume of cylinder.

$\text{Volume of remaining solid}=\text{Volume of cylinder- Volume of cone}$

$\text{Volume of remaining solid}=\pi r^{2} h- \frac{1}{3}\pi r^{2}h$

$\text{Volume of remaining solid}=\frac{3}{3}\pi r^{2} h- \frac{1}{3}\pi r^{2}h$

$\text{Volume of remaining solid}=\frac{2}{3}\pi r^{2} h$

Upon substituting our given values in the formula we will get,

$\text{Volume of remaining solid}=\frac{2}{3}\pi*6^{2}*10$

$\text{Volume of remaining solid}=\frac{2}{3}\pi*36*10$

$\text{Volume of remaining solid}=2*\pi*12*10$

$\text{Volume of remaining solid}=240\pi$

$\text{Volume of remaining solid}=753.9822368615503772\approx 753.98$

Therefore, the volume of remaining solid is 753.98 cubic cm.