Complete question is;
The place you get your hair cut has two nearly parallel mirrors 6.50 m apart. As you sit in the chair, your head is 3.00 m from the nearer mirror. Looking toward this mirror, you first see your face and then, farther away, the back of your head. (The mirrors need to be slightly nonparallel for you to be able to see the back of your head, but you can treat them as parallel in this problem.) How far away does the back of your head appear to be?
Answer:
13 m
Explanation:
We are given;
Distance between two nearly parallel mirrors; d = 6.5 m
Distance between the face and the nearer mirror; x = 3 m
Thus, the distance between the back-head and the mirror = 6.5 - 3 = 3.5m
Now, From the given values above and using the law of reflection, we can find the distance of the first reflection of the back of the head of the person in the rear mirror.
Thus;
Distance of the first reflection of the back of the head in the rear mirror from the object head is;
y' = 2y
y' = 2 × 3.5
y' = 7
The total distance of this image from the front mirror would be calculated as;
z = y' + x
z = 7 + 3
z = 10
Finally, the second reflection of this image will be 10 meters inside in the front mirror.
Thus, the total distance of the image of the back of the head in the front mirror from the person will be:
T.D = x + z
T.D = 3 + 10
T.D = 13m
Explanation:
The given data is as follows.
Charge (q) = 2 coulomb, Force (F) = 60 N
Now, it is known that the relation between electric field, force and charge is as follows.
Magnitude of electric field (E) = 
Hence, putting the given values into the above formula as follows.
Electric field (E) =
= 
= 30 N/C
Thus, we can conclude that the magnitude of the electric field at the place where the charge is located is 30 N/C.
Answer:
25 seconds (rounded up to nearest one second)
Explanation:
Cheetah's speed = 91.8 km/h
Gazelle's speed = 77.9 km/h
Both animals are running at full speed with the gazelle 97.3 m ahead.
Converting their respective speeds to m/s ;
Cheetah's speed = 
= 25.5 m/s
Gazelle's speed = 
= 21.6 m/s (correct to one decimal place)
Assuming the gazelle stops, cheetah will run at 25.5 m/s - 21.6 m/s = 3.9 m/s to catch its prey (gazelle).
Time = distance ÷ speed
The time cheetah will take to catch its prey = 97.3 m ÷ 3.9 m/s = 24.94871795 s = 25 seconds (rounded up to nearest one second)
Well from now he or she would have to be born in 2002.
