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sp2606 [1]
3 years ago
8

3.4.3 Quiz: Buoyancy

Physics
1 answer:
lara31 [8.8K]3 years ago
8 0

The word that belongs after "it's" is "volume".

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Derive the explicit rule for the pattern <br> 3, 0, -3, -6, -9,
pickupchik [31]
It is the last number minus 3
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What is the mass of an object that requires a force of 182 N to accelerate at a rate of 13 m/s?
Inga [223]

Answer:

m=14kg

Explanation:

Hello.

In this case, since the force is defined in terms of the mass and acceleration by:

F=m*a

We can easily compute the mass by solving for it:

m=\frac{F}{a}

Whereas the force is 182 N (kg*m/s²) and the acceleration is 13 m/s², therefore, we obtain:

m=\frac{182kg\frac{m}{s^2} }{13\frac{m}{s^2}}\\\\m=14kg

Best regards.

6 0
3 years ago
A piece of wire 29 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
skelet666 [1.2K]

Answer:

Explanation:

Total length of the wire is 29 m.

Let the length of one piece is d and of another piece is 29 - d.

Let d is used to make a square.

And 29 - d is used to make an equilateral triangle.

(a)

Area of square = d²

Area of equilateral triangle = √3(29 - d)²/4

Total area,

A = d^{2}+\frac{\sqrt3}{4}\left ( 29-d \right )^{2}

Differentiate both sides with respect to d.

\frac{dA}{dt}=2d- \frac{\sqrt3}{4}\times 2(29-d)

For maxima and minima, dA/dt = 0

d = 8.76 m

Differentiate again we get the

\frac{d^{2}A}{dt^{2}}= + ve

(a) So, the area is maximum when the side of square is 29 m

(b) so, the area is minimum when the side of square is 8.76 m

8 0
3 years ago
What is the mass of a ball that has 29j of potential energy and is lifted 2.0m?​
Salsk061 [2.6K]

Answer:

1.48kg

Explanation:

Here,

potential energy (P.E) = 29j

height (h) = 2m

acceleration due to gravity(g) =

9.8m {s}^{ - 2}

mass(m) = ?

we know,

P.E = mgh

or, 29 = m×9.8×2

or, 29/19.6 = m

or,m = 1.48kg

6 0
1 year ago
The minimum frequency of light needed to eject electrons from a metal is called the threshold frequency, ν0. find the minimum en
shusha [124]
The energy carried by the incident light is
E=hf
where h is the Planck constant and f is the frequency of the light. The threshold frequency is the frequency that corresponds to the minimum energy needed to eject the electrons from the metal, so if we substitute the threshold frequency in the formula, we get the minimum energy the light must have to eject the electrons:
E=hf=(6.63 \cdot 10^{-34}Js)(5.64 \cdot 10^{14}s^{-1})=3.74 \cdot 10^{-19}J
4 0
3 years ago
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