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2 years ago

When the flower below is rotated clockwise 90°, where will the red petal be in the image?

1 answer:

6 0

Hey I need a pic then I'll answer in the comments. If no pic then if a red petal is directly facing a side, then it will be facing the adjacent clockwise side.

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Please help. 8th grade science

Aneli [31]

Answer:

false

Explanation:

It doesn't the copper wire wouldn't even be pulled by the magnet at all and the electricity would stay inside of the the force of the copper wire

3 0

2 years ago

Please help!

julsineya [31]

Answer:

Answer:

3 g/cm

Explanation:

Mass of stone = 30 g

Initial volume of cylinder = 50 cm

Increased volume = 60 cm

Volume = 60-50

= 10 cm

Density of stone = Mass/Volume

= 30/10

= 3 g/ml as 1 ml = 1 cm

= 3 g/ml

Explanation:

6 0

2 years ago

It is important to use the correct drying tempture because it prevents shrinkage and will not damage the garment.

Nina [5.8K]

Answer:

fjowe

Explanation:

kbegtrf3g4ef j3kq4ef 3w4beysrf2w4er8f6ywgbaebf7v2wy4egdwa4i6e5

7 0

2 years ago

Read 2 more answers

A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist

7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

$P = VI$

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

$I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}$

b) The resistance <em>R</em><em> </em>of the heater is

$P = VI = (IR)I = I^2R$

where $V= IR$ is our familiar Ohm's Law.

$\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}$

$R = 110.8\:Ω$

8 0

2 years ago

Consider a steel cable with a diameter of 8.0 mm. Calculatethe stress in the cable when it holds a person weighing 850 N.Report

pishuonlain [190]

Answer:

stress = 16.9 MPa

Explanation:

The stress in the cable can be calculated as:

$\text{Stress = }\frac{F}{A}$

Where F is the force and A is the area. So, the area can be calculated as:

$A=\pi^{}\cdot r^2$

Where r is the radius. Since the radius is half the diameter, the radius is 4.0 mm and the area will be equal to:

$\begin{gathered} A=3.14(4\operatorname{mm})^2 \\ A=50.24\operatorname{mm}^2 \end{gathered}$

Then, replacing the force F by 850 N, and A by 50.24 mm², we get that the stress is equal to:

$\text{stress = }\frac{850N}{50.24mm^2}=16.9\text{MPa}$

Therefore, the answer is 16.9 MPa

7 0

10 months ago