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Nana76 [90]
3 years ago
15

Find the resistance of an electric light bulb if a current of 0.08 A flows when the potential difference across the bulb is 120

V.
Physics
1 answer:
lora16 [44]3 years ago
8 0
U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you
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Answer:

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Explanation:

Given that

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v² = u² - 2 g h

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Now by putting the values

v² = u² - 2 g h

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Answer:

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