Question

A ball is dropped off the side of a bridge after falling 1.55 s, what is its velocity.

Answer 1

Answer:

v = 15.19 m/s

Explanation:

As we know that when object is dropped from some height then initial speed of the object is taken as

$v_i = 0$

now for the final speed of object we can say that if acceleration is constant then the final speed will be given by kinematics equation

$v_f = v_i + at$

here we have

$a = 9.8 m/s^2$ (due to gravity)

now from this equation of motion

$v_f = 0 + (9.8)(1.55)$

$v_f = 15.19 m/s$