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3 years ago

A ball is dropped off the side of a bridge after falling 1.55 s, what is its velocity.

Physics

1 answer:

Scorpion4ik [409]3 years ago

9 0

Answer:

v = 15.19 m/s

Explanation:

As we know that when object is dropped from some height then initial speed of the object is taken as

$v_i = 0$

now for the final speed of object we can say that if acceleration is constant then the final speed will be given by kinematics equation

$v_f = v_i + at$

here we have

$a = 9.8 m/s^2$ (due to gravity)

now from this equation of motion

$v_f = 0 + (9.8)(1.55)$

$v_f = 15.19 m/s$

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Answer:

Velocity = 4.33[m/s]

Explanation:

The total energy or mechanical energy is the sum of the potential energy plus the kinetic energy, as it is known the velocity and the height, we can determine the total energy.

$E_{M}=E_{p} + E_{k} \\E_{p} = potential energy [J]\\E_{k} = kinetic energy [J]\\where:\\E_{p} =m*g*h\\E_{p} = 4*9.81*0.5=19.62[J]\\E_{k}=\frac{1}{2} *m*v^{2} \\E_{k}=\frac{1}{2} *4*(3)^{2} \\E_{k}=18[J]\\Therefore\\E_{M} =18+19.62\\E_{M}=37.62[J]$

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3 years ago

What is the gravity force between two stars with mass of 5,000,000 kg and 1,000,000 kg if the distance between them is 100 m

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Answer:

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Explanation:

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M1 = 5 x 10⁶kg

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Unknown:

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3 years ago

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Answer:

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