Question

A train approaching a crossing changes speed from 10 m/s to 25 m/s in 240 s. How can the train's acceleration be described?

Answer 1

Answer:

$\boxed{\text{The train is speeding up by 0.0625 m/s every second}}$

Explanation:

Acceleration (a) is the change in velocity (Δv) divided by the change in time (Δt).

$a = \frac{\Delta v}{\Delta t} = \frac{v_{2} - v_{1} }{t_{2} - t_{1}} \\\\a = \frac{25 - 10}{240 - 0}=\frac{15 }{240}=\text{0.0625 m/s}^{2}\\\\\ \boxed{\textbf{The train is speeding up by 0.0625 m/s every second}}$