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Solnce55 [7]
2 years ago
13

For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the

slower phase only) of 0.216 (in a cuvette with a pathlength of 1 cm) over the course of two minutes. Use the Beer-Lambert Law to calculate the concentration of product released over this time; the extinction coefficient of p-nitrophenol at 405 nm is 18,000 M-1 cm-1.
Chemistry
1 answer:
Aleks04 [339]2 years ago
4 0

Answer:

1.2x10⁻⁵M = Concentration of the product released

Explanation:

Lambert-Beer's law states the absorbance of a solution is directly proportional to its concentration. The equation is:

A = E*b*C

<em>Where A is the absotbance of the solution: 0.216</em>

<em>E is the extinction coefficient = 18000M⁻¹cm⁻¹</em>

<em>b is patelength = 1cm</em>

<em>C is concentration of the solution</em>

<em />

Replacing:

0.216 = 18000M⁻¹cm⁻¹*1cm*C

<h3>1.2x10⁻⁵M = Concentration of the product released</h3>
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A. 8600 J

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<u>Thermochemistry</u>

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Explanation:

<u>Step 1: Define</u>

[Given] <em>m</em> = 1600 g

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<u>Step 2: Find Heat</u>

  1. Substitute in variables [Specific Heat Formula]:                                           q = (1600 g)(0.450 J/g °C)(12 °C)
  2. Multiply [Cancel out units]:                                                                             q = (720 J/°C)(12 °C)
  3. Multiply [Cancel out units]:                                                                             q = 8640 J

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

8640 J ≈ 8600 J

Topic: AP Chemistry

Unit: Thermodynamics

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