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krok68 [10]
3 years ago
12

Explain why it may make more sense to colonize on Venus, rather than Mars.

Physics
2 answers:
Illusion [34]3 years ago
7 0

Venus is way closer.

SVEN [57.7K]3 years ago
6 0

Venus is closer, relatively the same size as the earth and has an atmosphere

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Assume that before separation, the weight of the milk bottle's contents (mixed milk and cream) is wmix. How does the combined we
finlep [7]

Answer:

Wsep = Wmix

Explanation:

When Cream and milk up in a bottle they might appear homogeneous but after the bottle must have settled down for a while i.e kept in a position without shaking the bottle. the contents ( cream and milk ) will be separated. this is because Milk and cream do not mix up just like some other liquids that don't mix-up. Wmix represents the weight of the bottle before separation while Wsep represents the weight after separation. but since both liquids are in the same bottle the weight after separation would remain the same

Wsep = Wmix

3 0
3 years ago
6.
Vikentia [17]

Answer:

Explanation:

Givens

vi = 0

a = 9.81

d = 4.50 m

vf = ?

Formula

vf^2 = vi^2 + 2 * a * d

Solution

Substitute the knowns into the formula

vf^2 =0 +  2 * 9.81 * 4.50

vf^2 = 88.29                          Take the square root of both sides.

sqrt(vf^2) = sqrt(88.29)    

vf = 9.40 m/s

3 0
3 years ago
An what would be needed to change an objects state of motion
VladimirAG [237]

Inertia: tendency of an object to resist changes in its velocity. An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.

~done by cessly420

mark brainliest please

hope this helped   :)

8 0
4 years ago
Venus has an average distance to the sun of 0.723 AU. In two or more complete sentences, explain how to calculate the orbital pe
Mice21 [21]

As per the question the distance of venus from sun is given as 0.723 AU

We have been asked to calculate the time period of the planet venus.

As per kepler's laws of planetary motion the square of time period of planet is directly proportional to the cube of semi major axis. mathematically

                                        T^{2} \alpha R^{3}

                                         ⇒ T^{2} = KR^{3} where is k is the proportionality  constant

We may solve this problem by comparing with the time period of the earth . We know that time period of earth is 365.5 days

Hence T_{1} =365.5 days

The distance of sun from earth is taken as 1 AU i.e the mean distance of earth from sun

Hence R_{1} =1 AU

The distance of venus from sun is 0.723 AU i.eR_{2} =0.723

From keplers law we know that-\frac{T_{1} ^{2} }{T_{2} ^{2} } =\frac{R_{1} ^{3} }{R_{2} ^{3} }

                            ⇒T_{2} ^{2} =T_{1} ^{2} *\frac{R_{2} ^{3} }{R_{1} ^{3} }

Putting the values mentioned above we get-

                                      T_{2} ^{2} =50,350.132851075

                                         ⇒ T_{2} =\sqrt{50,350.132851075}

                                        ⇒T_{2} = 224.388352752710 days.

Hence the time period of venus is 224.388352752710 days

                                         

                     






                           

7 0
4 years ago
Read 2 more answers
How do i calculate this?
Lesechka [4]

CAR 1

Momentum = Mass/Velocity

M = 2100/20

M = 105 m/s^2

CAR 2

Momentum = Mass/Velocity

M = 2100/30

M = 70 m/s^2

8 0
3 years ago
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