At the position of terminal speed the net acceleration of the ball will become zero
As we know that terminal speed will always reach when net force on the ball is zero and its speed will become constant.
So here at this position we can say



now when ball is moving at half of the terminal speed in upward direction then net force on the ball in downwards direction will be


here speed of the ball is half of the terminal speed

then we have


now acceleration will be given as

now we have

downwards
Need to draw it first.....
but there is no option here to draw .. why?
anyway , here the car is going with a uniform velocity..
so the acceleration of the car=0, a=0
so resistive force on the car=component along the inclined plane of the weight of the car=mg*cos(90-15)=960*9.8*cos 75=?
Answer:
what i don't understand the question
Explanation :
Using the law of conservation of energy
When two cars collide with each other then the momentum is same before collision and after collision but energy is changed after collision in form of heat and sound.
We know this collision is inelastic collision.
In Inelastic collision, when two objects collide with each other then the momentum is conserved but kinetic energy is not conserved.
This would be called a Joule. The formula for energy is <span>P.E. = mgh (otherwise known as the gravitational force formula, which is energy.) M is the mass in kilograms, and G is the acceleration due to gravity, which is actually (9.</span>8 m / s2<span> at the surface of the earth.) I hope this helps! ~Mia</span>