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4 years ago

A fine-grained sedimentary rock is known as _____.

Physics

1 answer:

Yakvenalex [24]4 years ago

5 0

The finer‐grained<span> s</span>edimentary rocks<span> are called shale, siltstone, and mudstone</span>

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A stationary horn emits a sound with a frequency of 228 Hz. A car is moving toward the horn on a straight road with constant spe

stiks02 [169]

Answer: 26.84 m/s

Explanation:

Given

Original frequency of the horn $f_o=228\ Hz$

Apparent frequency $f'=246\ Hz$

Speed of sound is $V=340\ m/s$

Doppler frequency is

$\Rightarrow f'=f_o\left(\dfrac{v+v_o}{v-v_s}\right)$

Where,

$v_o=\text{Velocity of the observer}\\v_s=\text{Velocity of the source}$

Insert values

$\Rightarrow 246=228\left[\dfrac{340+v_o}{340-0}\right]\\\\\Rightarrow 366.84=340+v_o\\\Rightarrow v_o=26.8\ m/s$

Thus, the speed of the car is $26.84\ m/s$

4 0

4 years ago

If a 10,000 g mass is suspended from a rope, what is the tensile force in the rope?

nadezda [96]

To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function

$F = ma\rightarrow F =mg$

Here,

m = mass

a = g = Gravitational acceleration

Replacing we have that the weight is

$W= (10kg)(9.8)$

$W = 98N$

Since the rope is taut and does not break, the net force on the rope will be zero.

$\sum F = 0$

$T-W = 0$

$T = W$

$T = 98N$

Therefore the tensile force in the rope is 98N

8 0

3 years ago

Zach, whose mass is 90 kg , is in an elevator descending at 12 m/s . the elevator takes 3.0 s to brake to a stop at the first fl

sweet-ann [11.9K]

Finding out the acceleration 12/3 = 4m/s^2
thus it is descending so the actual acceleration would be 9.8-4 = 5.8 m/s^2
the weight will be 90*5.8 = 522 N
522/9.8 = 53.2 kg

7 0

4 years ago

Read 2 more answers

it takes you 9.5 min to walk with an average velocity of 1.2m/s to the north from the bus stop to the museum entrance. what is y

MAVERICK [17]

Answer:

x=684m

Explanation:

v=velocity

x=displacement

t=time

equation: v=x/t

v=1.2m/s

x=?

t=9.5min=570s

1.2=x/570

570*1.2=x/570*570

x=684m

3 0

3 years ago

A resistor and a capacitor are connected in series across an ideal battery having a constant voltage across its terminals. (a) A

maks197457 [2]

Answer:

(a) D. Zero.

(b) C. Equal to the battery's terminal voltage.

Explanation:

The question is incomplete, see the complete question for your reference and information.

A resistor and a capacitor are connected in series across an ideal battery having a constant voltage

across its terminals. At the moment contact is made with the battery

(a) the voltage across the capacitor is

A) equal to the battery's terminal voltage.

B) less than the battery's terminal voltage, but greater than zero.

C) equal to the battery's terminal voltage.

D) zero.

(b) the voltage across the resistor is

A) equal to the battery's terminal voltage.

B) less than the battery's terminal voltage, but greater than zero.

C) equal to the battery's terminal voltage.

D) zero

A RC circuit is a circuit that is composed of both resistors and capacitors connect to a source of current or voltage.

basically when a voltage source is applied to an RC circuit, the capacitor, C charges up through the resistance, R

6 0

4 years ago