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Monica [59]
3 years ago
5

Place the following descriptions in the correct order (1 to 4) to explain how lightning forms.

Chemistry
1 answer:
bearhunter [10]3 years ago
5 0

Answer: A D C B

Explanation:

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Copper metal can exist as ______________ ions.
denis-greek [22]

Answer:

Copper metal can exist as <em><u>Cu+</u></em><em><u> </u></em><em><u>and </u></em><em><u>Cu2+</u></em><em><u> </u></em>

ions.

3 0
2 years ago
Given that E
bija089 [108]

The equilibrium constant of the reaction is 1.21 * 10^6 while the change in free energy is -34.7 kJ.

<h3>What is equilirium constant?</h3>

The equilibrium constant shows the extent of conversion of reactants to products.

Now we know from the Nernst equation that;

Ecell = E°cell - 0.0592/n logQ

E°cell = 0.52−0.16=0.36 V

Since Ecell = 0 V at equilibrium,

0 = 0.36 - 0.0592/1 log K

0.36  = 0.0592/1 log K

log K = 0.36/ 0.0592

K = antiog (0.36/ 0.0592)

K = 1.21 * 10^6

ΔG = -RT lnK

ΔG =-(8.314 * 298 * ln1.21 * 10^6)

ΔG =-34.7 kJ

Learn more about equilibrium constant:brainly.com/question/10038290

5 0
1 year ago
What is the oxidation number of manganese (Mn) in potassium permanganate (KMnO4)?
andrezito [222]

What is the oxidation number of manganese (Mn) in potassium permanganate (KMnO4)?

+3
+5
+6
+7

The oxidation number of manganese (Mn) in potassium permanganate (KMnO4) is +5. 

7 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!
KatRina [158]

Answer: A chlorine atom has an atomic number of 17 and a mass number of 38. This chlorine atom has 18 neutrons

Hope this helps :)

7 0
3 years ago
The mass of a single uranium atom is 4.70x10^-22 grams. How many uranium atoms would there be in 111 milligrams of uranium?
emmainna [20.7K]

2.4 x 10²² atoms

<h3>Further explanation</h3>

Atomic mass is the average atomic mass of all its isotopes  

In determining the mass of an atom, as a standard is the mass of 1 carbon-12 atom whose mass is 12 amu  

So the atomic mass obtained is the mass of the atom relative to the 12th carbon atom  

mass single Uranium atom=4.7 x 10⁻²² g

then for 111 mg=0.111 g

\tt \dfrac{0.111}{4.7\times 10^{-22}}=2.4\times 10^{22}

5 0
2 years ago
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