Answer:
M = 0.050 M
Explanation:
WE have an acid base reaction between NaOH and HCl. The reaction is as follow:
HCl + NaOH -------> NaCl + H₂O
As we can see, we have a balanced equation already, and we can also see that the mole ratio between the HCl and NaOH is 1:1, therefore we can use the following expression:
M₁V₁ = M₂V₂ 1: acid; 2: base
This expression is used when the reactions has reached the equivalence point. As we want to know the concentration of the base, we just solve for M₂ above so:
M₂ = M₁V₁ / V₂
All we have to do now is replace the given values and solve for the concentration:
M₂ = 0.15 * 27 / 81
<h2>
M₂ = 0.050 M</h2><h2>
This is the concentration of the base</h2>
Answer:
A sodium atom has one electron in the outer shell. A chlorine atom seven electrons in the outer shell. A sodium atom loses an electron to a chlorine atom. The sodium atom becomes a positive sodium ion.
Answer:
ok 3 = 9 15 i got 15 so what
Explanation:
At time t = 273.15 °C, the x-intercept occurs. According to Charles' law, an ideal gas's volume decreases as its temperature rises. At t = 273.15 °C, the graph's x-intercept, volume approaches zero.
<h3>Charles law experiment: what is it?</h3>
Describe the Charles Law experiment. Gases have a tendency to expand when heated, according to Charles' law (sometimes referred to as the law of volumes), an experimental gas law. The Kelvin temperature and the volume will be directly proportional when the pressure on a sample of the a dry gas is held constant, according to a current interpretation of Charles's law.
<h3>Which laws—Charles and Boyles—have similarities?</h3>
Boyle's law is formulated for systems with constant temperature, whereas Charles' law is formulated for systems with constant pressure.
<h3>To know more about Charles law visit:</h3>
brainly.com/question/16927784
#SPJ13
Answer:
See Explanation
Explanation:
Let us consider the first two reactions, the initial concentration of CO was held constant and the concentration of Hbn was doubled.
2.68 * 10^-3/1.34 * 10^-3 = 6.24 * 10^-4/3.12 * 10^-4
2^1 = 2^1
The rate of reaction is first order with respect to Hbn
Let us consider the third and fourth reactions. The concentration of Hbn is held constant and that of CO was tripled.
1.5 * 10^-3/5 * 10^-4 = 1.872 * 10^-3/6.24 * 10^-4
3^1 = 3^1
The reaction is also first order with respect to CO
b) The overall order of reaction is 1 + 1=2
c) The rate equation is;
Rate = k [CO] [Hbn]
d) 3.12 * 10^-4 = k [5 * 10^-4] [1.34 * 10^-3]
k = 3.12 * 10^-4 /[5 * 10^-4] [1.34 * 10^-3]
k = 3.12 * 10^-4/6.7 * 10^-7
k = 4.7 * 10^2 mmol-1 L s-1
e) The reaction occurs in one step because;
1) The rate law agrees with the experimental data.
2) The sum of the order of reaction of each specie in the rate law gives the overall order of reaction.
