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julia-pushkina [17]
4 years ago
9

a problem or issue in a human or natural environment caused by chemical reactions. Plz give me the URL as well.

Chemistry
1 answer:
MArishka [77]4 years ago
5 0
The problem or issue in a human or natural environment caused by chemical reactions would be smog. It is a kind of air pollution, originally named for the mixture of smoke and fog in the air.  <span>The atmospheric pollutants or gases that form </span>smog <span>are released in the air when fuels are burnt. When sunlight and its heat react with these gases and fine particles in the atmosphere, it is formed.</span>
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Consider the following balanced thermochemical equation for a reaction sometimes used for H₂S production: 1/8 S₈(s) + H₂(g) → H₂
castortr0y [4]

ΔH = -15.78 KJ when 25.0 g of S₈ reacts.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The given reaction balanced equation is:

1/8 S₈(s) + H₂(g) → H₂S(g)       ΔH = -20.22kj

Now,

When 1 mol will react, then ΔH = -20.2 × 8

                                                   = -161.6 KJ

When 1 mol of S8 = 8 × 32 g

                             = 256 g

When 256g of S8 react ΔH = -161.6 KJ

When 1 g reacts, ΔH = \frac{-161.6}{256}

                                  =- 0.63125 KJ

When 25 g reacts, ΔH = - 0.63125 × 25

                                     = -15.78 KJ

Thus from the above conclusion we can say that ΔH = -15.78 KJ when 25.0 g of S₈ reacts.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

#SPJ4

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2 years ago
How do you know that some substances in coffee beans are soluble?
Fantom [35]

Answer:

When you make coffee, some of the compounds from the ground coffee end up in the water, giving it the distinctive color, aroma, and flavor that we associate with coffee. The solubility of some coffee constituents varies depending on the temperature of the water.

Explanation:

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A calorimeter contains 500 g of water at 25°C.....

the temperature of the water inside the calorimeter is 39.4°C.....

The specific heat of water is 4.18 J/g-°C.

energy needed to heat the water = specific heat * mass * temp difference

= 4.18 J/g-°C * 500 g * (39.4°C - 25°C)

= 4.18*500*14.4

= 30096J

or approx. 30kJ

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