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Alex787 [66]
3 years ago
7

Which processes represent one chemical change

Chemistry
2 answers:
brilliants [131]3 years ago
5 0
I believe the answer is (3) since decomposition is a chemical change and melting is a physical change
Sedaia [141]3 years ago
4 0

Answer: (3) decomposition and melting

Explanation: Chemical change is one in which chemical composition of substance changes.

Physical change is one in which chemical composition of substance do not change.

Freezing is a process in which a liquid changes into solid phase when allowed to cool. Thus it is a physical change.

Melting : It is process in which a solid changes into liquid phase by providing heat. Thus it is a physical change.

Vaporization : It is process in which liquid changes into gaseous phase by providing heat. Thus it is a physical change.

Decomposition is a chemical reaction in which one substance decomposes to form two or more than two products. Thus the chemical composition change, and hence is a chemical change.

Combustion is a reaction in which a substance combines with oxygen gas to produce carbon dioxide, water and a lot of heat. Thus the chemical composition change, and hence is a chemical change.

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It changes from a liquid from to a solid.

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3 years ago
Determine moles of 1.5g of sodium carbonate.
KIM [24]

Answer:

0.014mol

Explanation:

Given parameters:

Mass of Na₂CO₃  = 1.5g

Unknown:

Number of moles  = ?

Solution:

Number of moles of a compound is mathematically expressed as;

  Number of moles  = \frac{mass}{molar mass}  

 Molar mass of  Na₂CO₃  = 2(23) + 12 + 3(16) = 106g/mol

 Number of moles = \frac{1.5}{106}   = 0.014mol

8 0
2 years ago
Answer these questions based on 234.04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given. R
Scilla [17]

How many protons does Thorium have? 90

How many neutrons does Thorium-234 have? 144

Calculate the mass defect for the isotope thorium-234 1.85864 amu

4 0
3 years ago
Read 2 more answers
An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit
Anon25 [30]

<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol

<u>Explanation:</u>

To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of triprotic acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL

Putting values in above equation, we get:

3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

7 0
2 years ago
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